Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,
y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
Answer:
because it doesn't have an equal sign.
Step-by-step explanation:
The given information is,
→ a = -8
→ b = -7
→ c = 6
Let's verify the problem,
→ (a+b) + c = a+ (b+c)
→ (-8 - 7) + 6 = -8 + (-7 + 6)
→ -15 + 6 = -8 - 1
→ -9 = -9
→ [ LHS = RHS ]
Hence, it is equal and verified.
FORMULA:
ANSWER:
We are given new side of square i.e, 2s + 3.
So, Area = (2s + 3)²
- (2s)² + (3)² + 2 × 2s × 3
- 4s² + 9 + 12s
Hence, The area of the new graph is a perfect square trinomial: __4__s² + __12__s +__9__.
Answer:
W = 1/2L - 4
Step-by-step explanation:
The width is 4 less than 1/2 of the length.
w = 1/2L - 4
