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faltersainse [42]
3 years ago
8

7th question help please

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0
Hey there! :)

You have to find the area of all of them and add it together

Formulas:

Area of a triangle ⇒ (b · h) ÷ 2
Area of a square ⇒ l · w

Square -

l = 5
w = 5

5 × 5 = 25

Triangle - 

b = 5
h = 5

(5 × 5) ÷ 2
   
25   ÷   2   = 12.5

There are 4 triangles

12.5 × 4 = 50

50 + 25 = 75

Surface area = 75 in
²

Hope this helps :)
vaieri [72.5K]3 years ago
3 0
Surface area of the pyramid= 4*(area of the triangle) + area of the square

Area of the triangle = (1/2)*base*height=(1/2)*5*5= 25/2 in²
Area of the square = 5*5 =25 in²

Surface area of the pyramid = 4*(25/2) + 25=2*25 + 25=75 in²
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ABCD∼EFGH AD=45 in. , EH=75 in. , and AB=30 in. What is EF ? Enter your answer in the box. EF = in.
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To determine the measure of side length EF, you must find the relationship between the 2 side lengths.

You should set these up as ratios of the length to the width. So, for ABCD, it is 30/45. Make this equal to x/75. If you simplify the first ratio to 2:3, you can then multiply by both numerator and denominator by 25 to get x = 25 in/ 75 in.

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