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3 years ago

Question is in photo! Will give BRAINLIEST to whoever answers correctly first!

Chemistry

1 answer:

jek_recluse [69]3 years ago

5 0

Answer:

A new element

Explanation:

As you add mopre and more protons and electrons and neutrons it keeps on crating new.

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Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 33.4 g of Fe reacts

konstantin123 [22]

The grams of Fe₂O₃ that are formed is 47.68 g

calculation

Step 1: write the equation for reaction

4 Fe +3O₂ → 2 Fe₂O₃

Step 2: find the moles of Fe

moles = mass÷ molar mass

= 33.4 g÷55.8 g/mol =0.5986 moles

Step 3 : use the mole ratio to determine the moles of Fe₂O₃

That is from equation above Fe:Fe₂O₃ is 4:2 therefore the moles of Fe₂O₃ is = 0.5986 moles x 2/4 =0.2993 moles

Step 4 : find the mass of Fe₂O₃

mass = mass x molar mass

The molar mass of Fe₂O₃ = (55.8 x 2 +(15.9 x3) = 159.3 g/mol

mass is therefore = 0.2993 moles x 159.3 g/mol =47.68 g

4 0

3 years ago

Read 2 more answers

An organic synthesis to make the pain reliever acetaminophen is supposed to produce 280 kg of product but instead produces 70 kg

Irina-Kira [14]

Answer: 75%

Explanation:

The following information can be gotten from the question:

Waste = 70kg

Theoretical yield = 280kg

Therefore, the actual yield will be the difference between the theoretical yield and the waste which will be:

= 280kg - 70kg = 210kg

The percent yield will now be:

= Actual yield / Theoretical yield × 100

= 210/280 × 100

= 3/4 × 100

= 75%

4 0

3 years ago

What is the percent composition of MgO2H2

zhannawk [14.2K]

41.38 % Mg

55.17 % O

3.45 % H

Explanation:

What is the percent composition of magnesium hydroxide Mg(OH)₂?

To find the percent composition we follow the next algorithm.

First we calculate the molar mass of Mg(OH)₂:

molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2

molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole

Now we devise the next reasoning:

if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H

then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H

X = (100 × 24) / 58 = 41.38 % Mg

X = (100 × 32) / 58 = 55.17 % O

X = (100 × 2) / 58 = 3.45 % H

Learn more about:

percent composition

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4 0

3 years ago

A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t

gulaghasi [49]

Answer:

$\large \boxed{\text{45.1 g/mol}}$

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Data:

t₂ = 222 s

t₁ = 175 s

M₁ = 28.01

Calculation :

$\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}$

3 0

3 years ago

What is the mass of 7.00 moles of H2O2

____ [38]

Answer:

0.206 mol H₂O₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis

Explanation:

Step 1: Define

7.00 moles H₂O₂

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O₂ - 2(1.01) + 2(16.00) = 34.02 g/mol

Step 3: Convert

$7.00 \ g \ H_2O_2(\frac{1 \ mol \ H_2O_2}{34.02 \ g \ H_2O_2} )$ = 0.205761 mol H₂O₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.205761 mol H₂O₂ ≈ 0.206 mol H₂O₂

8 0

3 years ago