Answer:
The true statement is a. Reductants reduce oxidants and become oxidized.
Explanation:
The principle characteristic of reductant is to donate electron and that donated electron is accepted by an oxidant.
As a result reductant become oxidized by reducing the oxidant which itself get reduced by accepting the electron from the reductant.
<h3>Water</h3>
<em>Specific heat is defined as the amount of heat one gram of a substance must absorb or lose to change its temperature by one degree Celsius.</em>
- For water, this amount is one calorie, or 4.184 Joules.
Answer:
109.7178g of H2O
Explanation:
First let us generate a balanced equation for the reaction. This is illustrated below:
2C3H8O + 9O2 —> 6CO2 + 8H2O
Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:
Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.
Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g
Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol
Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g
From the equation,
120.19184g of C3H8O produced 144.12224g of H20.
Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O
Boiling point ..................................................
