<u>Answer:</u> The enthalpy change of the reaction is 58 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the enthalpy change of the reaction is 58 kJ.
Friction, applying the brakes, and wind
The reaction for the formation of MgO(s):
2 Mg (s) + O2(g) -à
2MgO(s) ΔH = -601.24
kJ/mol
<span>The enthalpy
information is taken from: http://webbook.nist.gov/cgi/inchi?ID=C1309484&Mask=2</span>
From the equation and with an enthalpy change of -231 kJ:
-231 kJ * 2 mol Mg * (1/-601.24 kJ/mol) = 0.76841 mol Mg
Then, with the molar mass of MgO = 40.3,
0.76841 mol Mg *(2 mol MgO/2 mol Mg)* 40.3 g/mol MgO = <span>30.967 g MgO</span>
When water (H2O) is added to liquid isopropanol to form a solution, then polar isopropanol molecules are attracted to polar water molecules at the surface of the water. It forms a solution of rubbing alcohol.
<h3>Isopropanol and water in the solution</h3>
Isopropyl alcohol is water-soluble and forms hydrogen bonds with molecules of water (H2O).
When H2O is added to liquid isopropanol to form a solution, H2O spread in a uniform way in the solution.
These isopropanol molecules can surround H2O molecules, which are carried into the solution.
Learn more about isopropyl alcohol here:
brainly.com/question/799124
I am taking the same test ;)
1.) Single-displacement
AB + C --> AC + B
2.) Double-displacement
AB + CD --> AD + CB
3.) Synthesis
A + B --> AB
4.) Decomposition
AB --> A + B
Hope this helps!