Could someone help me with this too? Much appreciated! I am a bit stuck.

A 0.2121g sample of an organic compound was burned in a stream of oxygen and the carbon dioxide produced was collected in a stre

pav-90 [236]

Answer:

The answer to your question is: 17.26% of carbon

Explanation:

Data

CxHy = 0.2121 g

BaCO₃ = 0.6006 g

Molecular mass BaCO₃ = 137 + 12 + 48 = 197 g

Reaction

CO₂ + Ba(OH)₂ ⇒ BaCO₃ + H₂O

Process

1.- Find the amount of carbon in BaCO₃

197 g of BaCO₃ --------------- 12 g of Carbon

0.6006 g ---------------- x

x = (0.6006 x 12) / 197

x = 0.0366 g of carbon

2.- Calculate the percentage of carbon in the organic compound

0.2121 g of organic compound --------------- 100%

0.0366g -------------- x

x = (0.0366 x 100) / 0.2121

x = 17.26%

4 0

3 years ago

Al+hcl=alcl3+H balance

Mumz [18]

Answer:

Explanation:

Kindly answer the way I have written.

8 0

3 years ago

This question involves two calculations. The answer to the first part will be

ozzi

Answer :

(a) The mass of $Al_2O_3$ produced is, 15.2 grams.

(b) The percent yield of the reaction is, 72.5 %

Explanation :

Part (a) :

Given,

Mass of $Al$ = 85.1 g

Molar mass of $Al$ = 27 g/mol

First we have to calculate the moles of $Al$

$\text{Moles of }Al=\frac{\text{Given mass }Al}{\text{Molar mass }Al}=\frac{85.1g}{27g/mol}=3.15mol$

Now we have to calculate the moles of $Al_2O_3$

The balanced chemical equation is:

$4Al+3O_2\rightarrow 2Al_2O_3$

From the reaction, we conclude that

As, 4 moles of $Al$ react to give 2 moles of $Al_2O_3$

So, 3.15 moles of $Al$ react to give $\frac{2}{4}\times 3.15=1.58$ mole of $Al_2O_3$

Now we have to calculate the mass of $Al_2O_3$

$\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3$

Molar mass of $Al_2O_3$ = 102 g/mole

$\text{ Mass of }Al_2O_3=(1.58moles)\times (102g/mole)=161.2g$

Therefore, the mass of $Al_2O_3$ produced is, 161.2 grams.

Part (b) :

Now we have to calculate the percent yield of the reaction.

$\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield = 116.9 g

Theoretical yield = 161.2 g

Now put all the given values in this formula, we get:

$\text{Percent yield}=\frac{116.9g}{161.2g}\times 100=72.5\%$

Therefore, the percent yield of the reaction is, 72.5 %

8 0

3 years ago

What are the two most recent fossils that have been found in New york?

fgiga [73]

cie

Explanation:cioserra s ojs queengo o m me vengoe volo

4 0

3 years ago

Read 2 more answers

If an object moves in uniform circular motion in a circle of radius R=2.00 meters, and the object takes 5.00 seconds to

Minchanka [31]

Answer:

The centripetal acceleration of the object is $315.5\ m/s^2$ .

Explanation:

We have,

Radius of a circular path is 2 m

It takes 5 seconds to complete 10 revolutions. It means its angular velocity is :

$\omega=\dfrac{\Delta \theta}{\Delta t}\\\\\omega=\dfrac{2\pi \times 10}{5}\\\\\omega=12.56\ rad/s$

The centripetal acceleration of the object is given by :

$a=\omega^2 r\\\\a=(12.56)^2 \times 2\\\\a=315.5\ m/s^2$

So, the centripetal acceleration of the object is $315.5\ m/s^2$ .

5 0

3 years ago