Find the mass of 0.456 mol of Ca(OH)2 Please if you can show the work.
2 answers:
<h2>Answer:</h2>
<em>Hey, </em>
<h3><u>QUESTION)</u></h3>A) Let's first calculate the molar mass M of the molecule :
<em>M(Ca(OH)₂) = M(Ca) + 2M(O) + 2M(H) </em>
- M(Ca(OH)₂) = 40 + 2 x 16 + 2 x 1
- M(Ca(OH)₂) = 74 g/mol
B) Let's deduct the corresponding mass m :
<em>m = M x n </em>
- m = 74 x 0.456
- m = 33.744 g
- m ≈ 34,0 g
The mass of calcium hydroxide corresponding to this quantity of substance (in mol) is therefore 34 g.
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Answer:
C.
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