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2 years ago

Find the mass of 0.456 mol of Ca(OH)2 Please if you can show the work.

Chemistry

2 answers:

Tatiana [17]2 years ago

6 0

<h2>Answer:</h2>

<h3><u>QUESTION)</u></h3>

A) Let's first calculate the molar mass M of the molecule :

M(Ca(OH)₂) = 40 + 2 x 16 + 2 x 1
M(Ca(OH)₂) = 74 g/mol

B) Let's deduct the corresponding mass m :

m = 74 x 0.456
m = 33.744 g
m ≈ 34,0 g

The mass of calcium hydroxide corresponding to this quantity of substance (in mol) is therefore 34 g.

m_a_m_a [10]2 years ago

3 0

Answer:

Ca(OH)2 molecular weight. Molar mass of Ca(OH)2 = 74.09268 g/mol. This compound is also known as Calcium Hydroxide. Convert grams Ca(OH)2 to moles or moles Ca(OH)2 to grams. Molecular weight calculation: 40.078 + (15.9994 + 1.00794)*2 ››

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What type of reaction is AsCl+H2S --> As2S3+HCl

borishaifa [10]

Answer:

Double replacement:

Explanation:

Chemical equation:

2AsCl + 3H₂S → As₂S₃ + 6HCl

The given reaction is double displacement reaction. In this reaction arsenic trichloride and hydrogen sulfide react and produced arsenic sulfide and hydrogen chloride. In double displacement reaction both anion an cation of reactants are exchanged with each other.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

General equation:

AB + CD → AD +CB

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3 years ago

After some wood has completely burned in a fire, some of the matter that made up the wood has been destroyed.

nekit [7.7K]

The correct answer is D - When burning a log, the wood combined its components with oxygen. if you could capture the products (CO2, H2O, C, CO, etc), you would have a greater mass than what you started with, burning the log combined the log's components with oxygen in order to burn it.

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2 years ago

Read 2 more answers

Una muestra de oxígeno ocupa 4.2 litros a 760 mm de hg . ¿ cual será el volumen del oxigeno a 415 mm de hg , si la temperatura p

ddd [48]

Teniendo en cuenta la ley de Boyle, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Al aumentar el volumen, las partículas (átomos o moléculas) del gas tardan más en llegar a las paredes del recipiente y por lo tanto chocan menos veces por unidad de tiempo contra ellas. Esto significa que la presión será menor porque ésta representa la frecuencia de choques del gas contra las paredes.

De esta manera se relaciona la presión y el volumen, determinando la ley de Boyle que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:

P×V=k

Teniendo un estado inicial 1 y final 2, se cumple:

P₁×V₁= P₂×V₂

En este caso, se sabe que:

P₁= 760 mmHg
V₁= 4.2 L
P₂= 415 mmHg
V₂= ?

Reemplazando en la expresión matemática para la Ley de Boyle:

760 mmHg× 4.2 L= 415 mmHg× V₂

Resolviendo:

(760 mmHg× 4.2 L)÷ 415 mmHg= V₂

Finalmente, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Aprende más:

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1 year ago

What is the percent by volume of ethanol (C2H60, or ethyl alcohol) in the final solution when 90 mL of ethanol is diluted to a v

r-ruslan [8.4K]

Answer:

16.0%.

Explanation:

Volume percent of a substance is the ratio of the substance volume to the solution volume multiplied by 100.

V % of ethanol = (volume of ethanol / volume of the solution) x 100.

volume of ethanol = 90.0 mL, volume of the solution = 550.0 mL.

∴ V % of ethanol = (90.0 mL / 550.0 mL) x 100 = 16.36% ≅ 16.0%.

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2 years ago

what is the percent by mass of NaHCO3 in a solution containing 20.0 g of NaHCO3 dissolved in 600.0 ml of water

Ne4ueva [31]

%(NaHCO3)= ((mass NaHCO3)/(mass NaHCO3 + mass water))*100%

m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water

%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%

7 0

3 years ago