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alina1380 [7]
3 years ago
9

What is the intermediate step in the form (x + a)2 = b as a result of completing the

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Given:

The equation is:

x^2-12x+32=4

To find:

The result of completing the square for the given equation.

Solution:

We have,

x^2-12x+32=4

It can be written as:

x^2-12x=4-32

x^2-12x=-28

Now, we need to add half of square of coefficient of x, to complete the square.

Adding (\dfrac{-12}{2})^2 on both sides, we get

x^2-12x+(\dfrac{-12}{2})^2=-28+(\dfrac{-12}{2})^2

x^2-2(x)(6)+(-6)^2=-28+(-6)^2

x^2-2(x)(6)+(6)^2=-28+36                 [\because (-a)^2=(a)^2]

Using the formula (a-b)^2=a^2-2ab+b^2, we get

(x-6)^2=8

Therefore, the required equation after completing the square is (x-6)^2=8.

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Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

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= ±√(8281 - 3969)

= ±√4312

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So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

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