Answer:
x^2y^2 3y^2
Step-by-step explanation:
its a or the first choice
Answer:
Step-by-step explanation:
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
−
3
x
−
4
=
(
x
−
4
)
(
x
+
1
)
Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:
x
=
−
3
,
−
1
,
2
,
4
Note that when
x
is large, the
x
2
terms will dominate the values of the numerator and denominator, making both positive.
Hence the sign of the value of the rational expression in each of the intervals
(
−
∞
,
−
3
)
,
(
−
3
,
−
1
)
,
(
−
1
,
2
)
,
(
2
,
4
)
and
(
4
,
∞
)
follows the pattern
+
−
+
−
+
. Hence the intervals
(
−
3
,
−
1
)
and
(
2
,
4
)
are both part of the solution set.
When
x
=
−
1
or
x
=
4
, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).
When
x
=
−
3
or
x
=
2
, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.
Hence the solution is:
x
∈
[
−
3
,
−
1
)
∪
[
2
,
4
)
graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}
|4r + 8| ≥ 32
Split this expression into two expressions:
First ⇒ 4r + 8 ≥ 32 and second ⇒ 4r + 8 ≤ - 32
---
First expression: 4r + 8 ≥ 32
Subtract 8 from both sides.
4r ≥ 24
Divide both sides by 4.
r ≥ 6
---
Second expression: 4r + 8 ≤ - 32
Subtract 8 from both sides.
4r ≤ -40
Divide both sides by 4.
r ≤ -10
---
Your answer is 
A= 20 cause 5-2=3 and if the top is 23 it has to be 20
