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liberstina [14]
3 years ago
13

Which 0.1 M solution has a pH greater than 7? w 1. C6H1206 2.CH3COOH 3.КСІ 4.KOH

Chemistry
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

4) KOH

Explanation:

Trust

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`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
Which of the following are Cations? (Select all that apply)
AleksandrR [38]

Answer:

k(+)

NH4(+)

Al3(+)

Explanation:

cations are those elements who donate their electrons and we put a positive charge on it and receivers get negative charge and they are called anion.....Thank you so,much Please let me know how you feel and is helps you or not....

5 0
3 years ago
How many grams of pure naoh must be used to prepare 10.0 l of a solution that has a ph of 13? __________g?
padilas [110]

40 g NaOH. You must use 40 g NaOH to prepare 10.0 L of a solution that has a pH of 13.

<em>Step 1</em>. Calculate the pOH of the solution

pOH = 14.00 – pH = 14.00 -13 = 1

<em>Step 2</em>. Calculate the concentration of NaOH

[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-1) mol/L = 0.1 mol/L

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 10.0 L solution × (0.1 mol NaOH/1 L solution) = 1 mol NaOH

<em>Step 4</em>. Calculate the mass of NaOH

Mass of NaOH = 1 mol NaOH × (40.00 g NaOH/1 mol NaOH) = 40 g NaOH

8 0
4 years ago
PLEASE HELP MEEEEEEEEE
RideAnS [48]
Yea! what the person underneath me said
5 0
2 years ago
A student estimated the volume of a liquid in a beaker as 200.0 mL. When she poured the liquid into a graduated cylinder she MEA
Taya2010 [7]

Answer:

<h3>The answer is 0.91 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 198.2 mL

error = 200 - 198.2 = 1.8

So we have

P(\%) =  \frac{1.8}{198.2}  \times 100 \\  = 0.90817356205...

We have the final answer as

<h3>0.91 %</h3>

Hope this helps you

6 0
3 years ago
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