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katrin [286]
3 years ago
11

5. (10 Points) The volume of air in the lungs of a typical human is 6.0 L.

Chemistry
1 answer:
quester [9]3 years ago
8 0

Answer: the picture is work for number 1,2,4,5,7

Explanation: number 3: as the pressure in the volume decreases, the volume increases causing it to expand and eventually blow.

number 6: because the temperature and the amount of gas don’t change, these terms don’t appear in the equation. What Boyle’s law means is that the volume of a mass of gas is inversely proportional to its pressure. This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

hope this helps :))

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An amount of nitrogen undergoes a physical change and increases its volume. What can be known about this physical change?
Stella [2.4K]
The answer for The question is (D)The density changed
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4 years ago
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How many grams of oxygen are in 50.00 g of sucrose? Show work please
Serga [27]
You need the molercular mass of Sucrose.

You can either search the molecular formula of Sucrose and calculate the molecular mass, or search directly the molecular mass.

Here you have both:

Molecular mass of sucrose: 342.30 g / mol

Chemical formula of sucrose: C12 H22 O11 (if you want to just must multiply the number of each atom by its atomic mass to get the molecular mass).

Calculate the number of grams of O in that molecule:

O: 11 * 16.00 g/mol = 176.0 g of O.

Now use proportions:

176 g O / 342.30 g sucrose = x / 50.00 g sucrose

=> x = 50.00 g sucrose * 176.0 g O / 342.30 g sucrose =25.71 g O.

Answer: 25.17 g

5 0
3 years ago
I need to rearrange the letters to form a word. plz help
alekssr [168]
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4 0
3 years ago
(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0
4 years ago
The Hope diamond is the world's largest blue diamond; it weighs 44.4 carats. If one carat is defined as 200mg, calculate the mas
elena55 [62]
1 carat -------------- 200 mg
44.4 carat ---------- ( mass diamond  )

mass = 44.4 x 200 / 1

mass = 8880 mg

1 g ------------------------ 1000 mg
( mass in grams) --------- 8880 mg

mass in grams = 8880 x 1 / 1000

mass in grams = 8880 / 1000

= 8.88 g
5 0
3 years ago
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