<span>Not all elements have strong visible spectra in a flame</span>
When we describe the energy of a particle as quantized, we mean that only certain values of energy are allowed. ... In this case, whenever we measure the particle's energy, we will find one of those values. If the particle is measured to have 4 Joules of energy, we also know how much energy the particle can gain or lose. Quantized energy means that the electrons can possess only certain discrete energy values; values between those quantized values are not permitted
The answer would be c as the cart is not in motion therefor ruling out kinetic and it is completely at rest making all of it energy potential
T is amount after time t
<span>Ao is initial amount </span>
<span>t is time </span>
<span>HL is half life </span>
<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>
<span>( log At - log Ao) / log (1/2) = t / HL </span>
<span>log (At/Ao) / log (1/2) = t / HL </span>
<span>HL = t / [( log (At / Ao)) / log (1/2) ] </span>
<span>HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] </span>
<span>HL = 14.4 s / 2 = 7.2 seconds </span>
Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,

The expression of equilibrium constant
for the reaction will be:

Now put all the values in this expression, we get :


Therefore, the value of
at this temperature is 66.7