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Stolb23 [73]
3 years ago
14

Help asap please, explain why too!

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

Yes triangle ABC and DEF are similar.

Step-by-step explanation:

One rule of triangles is that all the angles in a triangle will add up to 180 degrees.

Now, first, you will figure out the remaining angle in triangle ABC.

  1. Add up 35 and 20. (35 + 20 =55)
  2. Subtract 55 from 180 (180-55= 125)
  3. When you add 125, 35, and 20, you get 180, which should happen due to the rule of all angles in a triangle add up to 180.

Now, in triangle DEF, one angle is 125 and the other is 35. To find the other angle add 125 and 35 and subtract the sum of those two numbers from 180.

  1. 125 + 35 = 160
  2. 180-160= 20

The remaining angle is 20 degrees

As you can see, triangle ABC shares the same angles as triangle DEF.

This tells you that triangle ABC and triangle DEF are both similar due to the fact that they have the same measurements of triangles.

You can also tell they are similar because two angles in triangle ABC equal two angles in triangle DEF because of the Angle-Angle (AA) Similarity

I hope this explanation helped and have a good day!

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I would appreciate this a lot if someone could help me with this.
VARVARA [1.3K]

Answer: 1 - 2 = u got this

Step-by-step explanation:

6 0
2 years ago
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the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
2 years ago
Write 2x + y = 17 in slope-intercept form. <br><br> Plz help me out here
Tatiana [17]

Answer:

y=-2x+17

Step-by-step explanation:

5 0
2 years ago
Function 1: Sam is 150 feet below sea level in a cave and trying to climb back out to safety at zero elevation. He climbs at a r
prisoha [69]

Answer:

Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3.

7 0
2 years ago
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Can someone help meeeeee
11Alexandr11 [23.1K]

Answer:

Area of shaded rectangle = 42 cm²

55%

Step-by-step explanation:

The length of the shaded area is equal to the length of the white rectangle.

Therefore, length of shaded rectangle = 7 cm

The width of the shaded rectangle is equal to the length of the white rectangle <u>minus</u> two widths of the white rectangle.

Therefore, width = 7 - (2 x 0.5) = 6 cm

Area of shaded rectangle = width x length

                                          = 6 x 7

                                          = 42 cm²

----------------------------------------------------------------------------------------------

Perimeter of a square = 4 × side length

If the perimeter of the square is 40 cm,
then the side length = 40 ÷ 4 = 10 cm

Area of a square = side length x side length

⇒ area of this square = 10 x 10 = 100 cm²

To determine the shaded area, calculate the areas of the 2 white triangles and subtract these from the area of the square.

Area of a triangle = 1/2 x base x height

⇒ area of left triangle = 1/2 x (10 - 7) x 10 = 15 cm²

⇒ area of right triangle = 1/2 x 10 x (10 - 4) = 30 cm²

Therefore, shaded area = 100 - 15 - 30 = 55 cm²

To calculate the percentage, divide the shaded area by the area of the square and multiply by 100:

(55 ÷ 100) × 100% = 55%

7 0
2 years ago
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