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Stolb23 [73]
3 years ago
14

Help asap please, explain why too!

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

Yes triangle ABC and DEF are similar.

Step-by-step explanation:

One rule of triangles is that all the angles in a triangle will add up to 180 degrees.

Now, first, you will figure out the remaining angle in triangle ABC.

  1. Add up 35 and 20. (35 + 20 =55)
  2. Subtract 55 from 180 (180-55= 125)
  3. When you add 125, 35, and 20, you get 180, which should happen due to the rule of all angles in a triangle add up to 180.

Now, in triangle DEF, one angle is 125 and the other is 35. To find the other angle add 125 and 35 and subtract the sum of those two numbers from 180.

  1. 125 + 35 = 160
  2. 180-160= 20

The remaining angle is 20 degrees

As you can see, triangle ABC shares the same angles as triangle DEF.

This tells you that triangle ABC and triangle DEF are both similar due to the fact that they have the same measurements of triangles.

You can also tell they are similar because two angles in triangle ABC equal two angles in triangle DEF because of the Angle-Angle (AA) Similarity

I hope this explanation helped and have a good day!

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The sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

<h3>Sum of expressions</h3>

Expressions are equations separated by mathematical signs. This expressions are known to contains certain unknowns

Given the following expression

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We are to take the sum of both expression to have:

f(x) = 10x^2 +7x+6 + 6x + 5

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f(x) = 10x^2 + 13x + 11

Hence the sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

Learn more on sum of functions here: brainly.com/question/11602229

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Answer this question. please​
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Answer:

\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$  .}}

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

<u>Height</u><u> </u><u>:</u><u>-</u>

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\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}

\rule{200}2

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<u>TSA </u><u>of </u><u>cuboid</u><u> </u><u>:</u><u>-</u><u> </u>

\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}

<u>Put </u><u>on</u><u> the</u><u> respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}=  2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}=  62 cm^2}}}

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