Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
Answer:
8.69 × 10^4
For a clearer answer look at the image.
Step-by-step explanation:
10² + 10² = 10^4
5.84 + 2.85 = 8.69
8.69 × 10^4
The answer would be 84 because 2miles is equal to 24 minutes so you would break that in half down to one mile. One mile would be 12 minutes. So you would multiply 12 times 7 which equals 84 which would be your answer.
Answer:
17
Step 1: rerrange the data
8 , 10, 12, 14, 17, 19, 19, 22, 24
Q2 is the median
see that the middle number is 17
Okay try to round the whole number and see if you can solve that should help you
