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Debora [2.8K]
2 years ago
5

Find the area of the figure.

Mathematics
2 answers:
Gelneren [198K]2 years ago
8 0

Answer:

64 + 28 = 92

Step-by-step explanation:

Split the figure in half creating two triangles and a square.

length and width for the square would be 8ft and 8ft. Multiply both for 64 to be the area.

7ft and 4ft are the height and base for the triangles.

In this case, just multiple 7 and 4 because normally you would need to divide the product by 2 however since there are two triangles it negates the step.

Mashutka [201]2 years ago
5 0

Answer:

92ft^2

Step-by-step explanation:

you have to find the are of the triangle and subtract it from the area of the rectangle.

area of the triangle is 28ft^2

area of the rectangle is 120ft^2

120-28 =  92

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The lengths of the diagonals of a rhombus are 18 cm and 24 cm. What is its perimeter and what is the distance between the parall
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Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

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