2x^3+x^2-15x factored completely would be: <em>x(x+3)(2x-5).</em> Not sure which answer choice but I hope that I was some help.
The absolute value of x is simply x and followed by the expression.
X + 1 + x + 1 <_ 2
2x + 2 <_ 2
2x <_ 0
X <_ 0
Basically all values that follow this inequality will most likely hold true.
For instance. -1.
-1 + 1 = 0
Absolute value of -2 = 2.
2 is equal to 2. This expression holds true.
First you solve for y.
5x+ y= 12 so Y= 12-5x
And plug it into the next equation
3x- 3(12-5x) = 18
Distribute
3x-36+15x=18
Add 36 to both sides
3x+ 15x= 54
18x= 54 ... divide
x= 3
And you can plug in x to solve for Y
5(3) + y = 12
15+ y = 12 ...subtract 15 from both sides
y= -3
9514 1404 393
Answer:
C. 2 2/5
Step-by-step explanation:
Put in the given value of y and solve for x.
6 = 5x -6
12 = 5x . . . . . . . . . add 6
12/5 = x = 2 2/5 . . . divide by 5, express as mixed number
