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Luda [366]
3 years ago
12

A2. Find y' and y" for y^2 = x^2+ sinxy

Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:

y'   = (2x + y cosxy)/(2y + x cosxy)

Step-by-step explanation:

Using implicit differentiation:

y^2 = x^2 + sin xy

2y y' = 2x + cos xy  * (xy' + y)

2y y' = 2x + xy' cos xy + y cos xy

2y y' - xy' cosxy = 2x + ycos xy

y'   = (2x + y cosxy)/(2y - x cosxy)

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4 0
3 years ago
A poster is to have a total area of
Neko [114]

Answer:

Dimensions of printed area

w = 8.95 cm

h = 13.44 cm

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Step-by-step explanation:

Lets call  " x "  and  "y" dimensions of the poster area  ( wide and height respectively) . Then

A(t)  =  180 cm²  = x*y      y  =  180/ x

And the dimensions of printed area is

A(p) = ( x - 2 ) * ( y - 3 ) then  as y  = 180/x we make A function of x only so

A(x)  =  ( x - 2 ) * ( 180/x  - 3 )     ⇒  A(x)  = 180 - 3x - 360/x +6

A(x)  = - 3x  - 360 /x + 186

Taking derivatives on both sides of the equation we get:

A´(x)  = -3  + 360/ x²  

A´(x)  = 0    -3  + 360/ x²  = 0     -3x²  +  360  = 0

x²  = 120       ⇒   x = √120       x  =  10.95 cm

And  y  =  180 / 10.95 ⇒         y  =  16.44 cm

Then x and y are the dimensions of the poster then according to problem statement

w of printed area is    x - 2  =  10.95 - 2   =  8.95 cm

and  h  of printed area is  y - 3  = 16.44 - 3  = 13.44 cm

And the largest printed area is  w * h  = ( 8.95)*(13.44)

A(max) = 120.28 cm²

   

 

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A pineapple costs $2.50
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Answer:

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Step-by-step explanation:

                                             

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