All categories

2 years ago

If the fifth term in a geometric sequence is 1∕27 and the common ratio is 1∕3, find the explicit formula of the sequence.

Mathematics

1 answer:

Snezhnost [94]2 years ago

5 0

Answer:

add my sc = bmic ava, no spaces

or add my discord = XoXo_ava

Step-by-step explanation:

:) hope i can help bbg/bbb

You might be interested in

What is the area of a triangle with a<br> base of 6m and a height of 7m

Veronika [31]

Answer:

It is 21

Step-by-step explanation:

5 0

3 years ago

Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of

Luda [366]

Answer:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

4 0

3 years ago

If a polynomial function f(x) has roots -8,1, and -6i , what must also be a root of f(x) ?

kap26 [50]

Heya !

In mathematics, the complex conjugate root theorem states that if P is a polynomial in one variable with real coefficients, and a + bi is a root of P with a and b real numbers, then its complex conjugate a − bi is also a root of P.

Here , one complex root is given -6i hence , the other must be 6i.

Hope it helps you ! :)

6 0

2 years ago

Write the function whose graph is the graph of y=l x l but is shifted up 9 units.

Olenka [21]

The function is y = IxI + 9

Step-by-step explanation:

Let us revise the translation of a function

If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k

∵ y = IxI

∵ The graph of the function is shifted 9 units up

- That means the graph of the function is translated 9 units, up

∵ The equation of the function f(x) whose graph shifted k units

up is f(x) + k

∵ k = 9

∴ The equation of the function is y = IxI + 9

The function is y = IxI + 9

Look to the attached figure for more understand

Learn more:

You can learn more about the translation in brainly.com/question/2451812

#LearnwithBrainly

8 0

3 years ago

M<1=2x-y<br> m<4=x-y<br> m<8=118

Mrrafil [7]

The second one hoped i helped :D

6 0

2 years ago