ANSWER
The correct answer is
EXPLANATION
The expression given to us is,
We plug in
. That means we substitute 12 wherever we see x to obtain,
We simplify the parenthesis first to obtain,
Hence the expression evaluates to
Answer:
A. 2.50
Step-by-step explanation:
25 ÷ 2 = 12.5
15 - 12.5 = 2.50
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
Complete the recursive formula of the geometric sequence 16\,,\,3.2\,,\,0.64\,,\,0.128,...16,3.2,0.64,0.128,
Nastasia [14]
Answer:
for all n>0, 
Step-by-step explanation:
Let 
be the sequence described.
A geometric sequence has the following property: there exists some r (the ratio of the sequence) such that 
forr all n>0.
To find r, note that
Similarly
Thus 
for all n>0, and
Answer:
AA similarity theorem
Step-by-step explanation:
we know that
<u>AA (Angle-Angle) Similarity</u> states that In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar
In this problem we have that
∠BCA=∠ECD ----> by vertical angles
∠BAC=∠DEC ---> because AB is parallel to ED (alternate interior angles)
therefore
Triangles ABC and EDC are similar by AA similarity theorem
