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3 years ago

Most people will experience hyposmia at some point in their life. OA True OB. False

Physics

2 answers:

oksano4ka [1.4K]3 years ago

6 0

Answer:

True

Explanation:

It happens every time you get a cold or something. It just means you partially lose your sense of smell

suter [353]3 years ago

5 0

Answer:

False

Explanation:

it is very rare to get hyposmia

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Compare the two circuit diagrams If one of the resistors is turned off (a light bulb goes out), what happens to the other resist

ella [17]

Answer:

it’s C

Explanation:

i just took the test

8 0

3 years ago

If a dog ran at 5m/s,how far would it run in 45 s?

ZanzabumX [31]

Answer:

225 meters

Explanation:

45*5 or 225 meters.

Hope this helps plz hit the crown :D

3 0

3 years ago

Read 2 more answers

An object with mass 80 kg moved in outer space. When it was at location <7, -34, -7> its speed was 14.0 m/s. A single cons

Sergio [31]

Answer:

W = -2080 J

Explanation:

initial position vector of the object is given as

$r_i = 7\hat i - 34\hat j - 7 \hat k$

similarly final position vector is given as

$r_f = 12\hat i - 42\hat j - 11\hat k$

now the displacement of the object is given as

$\vec d = \vec r_f - \vec r_i$

now we will have

$\vec d = (12\hat i - 42\hat j - 11\hat k) - (7\hat i - 34\hat j - 7 \hat k)$

$\vec d = 5\hat i - 8\hat j- 4\hat k$

now the force on the object is given as

$\vec F = (200\hat i + 460 \hat j - 150 \hat k)$

so here in order to find the work done

$W = \vec F . \vec d$

$W = (200\hat i + 460 \hat j - 150 \hat k). (5\hat i - 8\hat j- 4\hat k)$

$W = 1000 - 3680 + 600 = -2080 J$

7 0

3 years ago

ring a race a swimmer completes two laps. The first lap is From point A to B; the second is from B to A. Each lap is 60 meters l

cupoosta [38]

Answer:

Total time to complete the race = 45 sec

Explanation:

We have given that each lap is 60 m long

Average speed for the first lap = 2 m/sec

So time taken to complete the first lap $time\ t=\frac{distance}{speed}=\frac{60}{2}=30sec$

Average speed for second lap = 2 m/sec

So time taken to cover the second lap $time\ t=\frac{distance}{speed}=\frac{60}{4}=15sec$

So total time to complete the race = 30 +15 =45 sec

4 0

3 years ago

a load of 400 Newton is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the dis

Len [333]

Answer:

solution,
Given
load =400N
ld=0.2m
ed=0.6m
effort =150N

Explanation:

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

7 0

3 years ago