Answer:
v = 3.6m / s
, θ = 56º
Explanation:
This is a relative speed exercise, let's use the Pythagorean theorem
v = √ (v₁² + v₂²)
where v₁ is the speed of the sea still water and v₂ the speed of the current
let's calculate
v = √ (2² + 3²)
v = 3.6m / s
to find the direction we use trigonometry
tan θ = v₂ / v₁
θ = tan⁻¹ (v₂ / v₁)
let's calculate
θ = tan⁻¹ (3/2)
θ = 56º
If it soaks into the earths surface it becomes ground water
Answer:
T₂=659.25 K
Explanation:
Given that
W= 25 J
Qr = 20 J
T₁ = 20⁰ = 20 +273 = 293 K
The minimum temperature of the hot reservoir = T₂
If the engine is Carnot engine then
Qa= W+ Qr
Qa=25 + 20 J
Qa= 45 J
T₂=659.25 K
Therefore the temperature of hot reservoir will be 659.25 K
Answer:
R' = 4R
The resistance will become 4 times the initial value.
Explanation:
The resistance of a wire at room temperature, is given by the following formula:
R = ρL/A ----------- equation 1
where,
R = Resistance of wire
ρ = resistivity of the material
L = Length of wire
A = Cross-sectional area of wire
Now, if the length (L) is multiplied by 4, then resistance will become:
R' = ρ(4L)/A
R' = 4 (ρL/A)
using equation 1:
<u>R' = 4R</u>
<u>The resistance will become 4 times the initial value.</u>
Answer:
According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D, the object is moving in the negative direction (i.e., has a negative velocity) and is speeding up.
