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kkurt [141]
3 years ago
5

Describe the relationship between a compass and a magnet. Use C.E.R. Your C.E.R should have a one-sentence claim, three pieces o

f evidence, and two reasoning sentences that explain why you chose your evidence.
Physics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

ANSWER KEY Relationship of Magnets CER

Claim (Write one sentence stating the cause and effect relationship of magnets.)

In magnets, like poles repel, whereas opposite poles attract.

Evidence (Provide scientific data to support your claim. The evidence should include how attraction and repulsion is demonstrated by the matchbox cars and the position of the poles of the magnets.)

When the North Pole of the magnet (orange) and the South Pole of the magnet (green) came close to one another they attracted and when the North Pole of the magnet (orange) and the North Pole of the magnet (orange) came close to one another, they repelled. The South Pole against the South Pole repelled as well. Therefore confirming that opposite poles attract and like poles repel. We were able to record data to show the distance that each car traveled by using either attraction or repulsion. Four out of five cars give evidence that the repulsion, created by opposing poles, had the stronger force.  

Reasoning (Explain why your evidence supports your claim. Describe how the poles of the magnet determine whether magnets attract or repel and how your evidence allowed you to see the force of the attraction or repulsion.)

Magnets have an invisible force around them, called the magnetic field, which has North and South Poles. The opposite poles attract and like poles repel. We saw this through completing the activity by seeing and measuring the distance that was traveled by each car using attraction and repulsion.

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An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

Ke= 6.6E-34/880nm x 18.2E -31.

5.6E-27/18.2E-31

= 3 x 10⁴ Volts

4 0
3 years ago
Help plzzzz thank youu
dybincka [34]
The answer is B I hope this helps luv
5 0
3 years ago
A person lifts a 25 kg box of old sports equipment at an angle of 75 degrees to the vertical to a shelf 2.6 meters above. How mu
kogti [31]

Answer:

164.87 J

Explanation:

From the question,

Work done (W) = mghcosθ........................ Equation 1

Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical

Given: m = 25 kg, h = 2.6 meters, θ = 75°.

Constant: g = 9.8 m/s²

Substitute these value into equation 1

W = 25×9.8×2.6×cos75°

W = 164.87 J.

6 0
3 years ago
An ore sample weighs 17.50 N in air. When the sample
zysi [14]

Answer with Explanation:

We are given that

Weight of an ore sample=17.5 N

Tension in the cord=11.2 N

We have to find the total volume and the density of the sample.

We know that

Tension, T=W-F_b

F_b=buoyancy force

T=Tension force

W=Weight

By using the formula

11.2=17.5-F_b

F_b=17.5-11.2=6.3 N

F_b=V_{object}\times \rho_{water}\cdot g

Where

V_{object}=Volume of object

\rho_{water}=1000 kgm^{-3}=Density of water

g=9.8 ms^{-2}=Acceleration due to gravity

Substitute the values then we get

6.3=9.8\times 1000\times V_{object}

V_{object}=\frac{6.3}{9.8\times 1000}=6.43\times 10^{-4} m^3

Volume of sample=6.43\times 10^{-4} m^3

Density of sample,\rho_{object}=\frac{Mass}{volume_{object}}

Where mass of ore sample=1.79 kg

Substitute the values then, we get

\rho_{object}=\frac{1.79}{6.43\times 10^{-4}}=2.78\times 10^3 kg/m^3

Density of the sample=2.78\times 10^{3} kgm^{-3}

7 0
3 years ago
Which of the following is a derived unit?<br><br> ampere<br> newton<br> second<br> kilogram
Soloha48 [4]

Newton is your answer.

ampere, second, kilograms, are all base units.

hope this helps

5 0
3 years ago
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