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NemiM [27]
2 years ago
10

What energy store is in the torchBEFORE it gets switched on?​

Physics
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

Chemical energy

Explanation:

The energy in the torch is stored as chemical energy before the torch gets switch on.

The chemical energy energy in the battery of cell will power the cell and allows it to produce light.

  • Chemical energy is a form of potential energy.
  • The electrolytes within the battery are capable of producing electric current.
  • So the chemical energy is transformed into electrical energy which is used to produce the light of the torch.
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Suppose the polar bear was running on land instead of swimming. If the polar bear runs at a speed of about 8.3 m/s, how far will
olga_2 [115]

Answer:

298800 m

Explanation:

v =  \frac{d}{t}

V=speed

d=distance

t=time

d = vt

Change hours to seconds

It will be 36000s

8.3m/s * 36000s

=298800m

8 0
3 years ago
8. What is the mass of a toy car with a speed of 12.5 m/s and 47500 J of kinetic energy?
Alla [95]

Answer:

608kg

Explanation:

Formula : <u>Kinetic</u><u> </u><u>energy</u><u> </u>

½ ×mass x speed²

<u>47500</u>

½×12.5²

=608 Kg

7 0
3 years ago
Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j
AlekseyPX

1) Fundamental units of \Psi are [\frac{mol}{m\cdot s^2}]

2) Fundamental units of \Phi are [\frac{mol}{m^3}]

Explanation:

The equation for the variable \rho is

\rho =\frac{2\gamma \Phi+\Psi}{rg}

where we have:

\rho measured in [\frac{mol}{ft^3}]

\gamma measured in [\frac{J}{kg}]

r measured in [in]

g measured in [\frac{m}{s^2}]

We can re-write the equation as

\rho rg = 2\gamma \Phi + \Psi

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, \Psi must have the same units of \rho r g. So,

[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of \Psi are

[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]

2)

The term 2\gamma \Phi must have the same units of \Psi in order to be added to it. Therefore,

[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]

We also know that the units of \gamma are [\frac{J}{kg}], therefore

[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]

And so, the fundamental units of \Phi are

[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]

However, the Joules can be written as

[J]=[kg][\frac{m^2}{s^2}]

Therefore

[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]

#LearnwithBrainly

7 0
3 years ago
You might have heard the phrase ‘hot air rises'. Name the process of transferring energy using moving gas or liquid.
Blizzard [7]

Answer: Convection

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4 0
3 years ago
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