Answer:
Final velocity will be 314.6 m/sec
Distance traveled = 1314.24 m
Explanation:
We have given initial velocity u = 233 m/sec
Acceleration 
Time t = 4.8 sec
From first equation of motion 
, here v is final velocity, u is initial velocity and t is time
So 
Now we have to find distance traveled
From second equation of motion
So distance traveled in given time will be 1314.24 m
Answer:
no
Explanation:
i did it and got it right.
The sum of more than one velocity vector.
Or the sum of an initial velocity vector and an acceleration vector integrated over time.
Answer:
v = 747.83 m/s
Explanation:
given,
mass of bullet, m = 10.7 g
= 0.0107 Kg
mass of the wooden plank, M = 4588 g = 4.588 Kg
speed of the block and the bullet together, V = 1.74 m/s
initial speed of the plank = 0 m/s
using conservation of momentum
m v + M u = ( M + m ) V
0.0107 x v + 0 = (4.588 + 0.0107) x 1.74
0.0107 v = 8
v = 747.83 m/s
now, speed of the bullet is equal to 747.83 m/s.
