A man is standing on the shore of a beach, up to his knees in water. Every second two waves hit him. What is the frequency of th
1 answer:
Answer:
f = 2 Hz
Explanation:
The frequency of a wave is defined as the no. of waves passing per unit of time. Therefore, the frequency of a wave can be calculated by the following formula:
where,
f = frequency of the wave = ?
t = time passed = 1 s
n = no. of waves passing in time t = 2
Therefore,
<u>f = 2 Hz</u>
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Due to equilibrium of moments:
1) The weight of the person hanging on the left is 250 N
2) The 400 N person is 3 m from the fulcrum
3) The weight of the board is 200 N
Explanation:
1)
To solve the problem, we use the principle of equilibrium of moments.
In fact, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
The moment of a force is defined as:
where
F is the magnitude of the force
d is the perpendicular distance of the force from the fulcrum
In the first diagram:
- The clockwise moment is due to the person on the right is
where is the weight of the person and
is its distance from the fulcrum
- The anticlockwise moment due to the person hanging on the left is
where is his weight and
is the distance from the fulcrum
Since the seesaw is in equilibrium,
So we can find the weight of the person on the left:
2)
Again, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
- The clockwise moment due to the person on the right is
where is the weight of the person and
is its distance from the fulcrum
- The anticlockwise moment due to the person on the left is
where is his weight and
is the distance from the fulcrum.
Since the seesaw is in equilibrium,
So we can find the distance of the person on the right:
3)
As before, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.
- The clockwise moment around the fulcrum this time is due to the weight of the seesaw:
where is the weight of the seesaw and
is the distance of its centre of mass from the fulcrum
- The anticlockwise moment due to the person on the left is
where is his weight and
is the distance from the fulcrum
Since the seesaw is in equilibrium,
So we can find the weight of the seesaw:
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The kinetic energy K = 0.5 * m * v² must be equal to the potential energy U = m * g * h.
m mass
v velocity
h height
g = 9.81m/s²
The mass m cancels out:
0.5 * v² = g * h
Solve for height h and transform to distance traveled.
(sin (4°) = height / distance)
m mass
v velocity
h height
g = 9.81m/s²
The mass m cancels out:
0.5 * v² = g * h
Solve for height h and transform to distance traveled.
(sin (4°) = height / distance)