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Studentka2010 [4]
3 years ago
7

A good example of kinetic energy would be_____.

Physics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

B.) a stretched rubber band

Explanation:

-

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if a 5-kg bowling ball is projected upward witha velocity of 2.0 m/s, then what is the recoil velocity of the Earth(mass=6.0×10^
vitfil [10]

by the concept of momentum conservation we can say

if net force on a system of mass is ZERO then its momentum will remain conserved

Here a ball is projected upwards so if we take Ball + Earth as a system then total momentum of the system will remain conserved

Initially when ball is on the surface of earth the system has zero momentum and hence we can say after throwing the ball momentum of earth + ball must be zero

now using same equation we can say

P_{ball} + P_{earth} = 0

m_1v_1 + m_2v_2= 0

given that

m_1 = 5 kg

v_1 = 2 m/s

m_2 = 6 * 10^{24} kg

from above equation velocity of earth will be

v_2 = \frac{m_1 v_1}{m_2}

v_2 = \frac{5*2}{6 * 10^{24}}

v_2 = 1.67 * 10^{-24} m/s

so above will be the recoil speed of earth

3 0
3 years ago
A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8 coulombs. What is the electric field at t
Alborosie
The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge. 

E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.

So E=(k*q)/r² 

When we input the numbers we get that electric field E of a point chage q is:

E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B. 
6 0
3 years ago
Read 2 more answers
Land masses that move on Earth are called: a. Continents b. Tectonic continents c. Tectonic plates d. Rock Masses
Andrew [12]

Answer:

c. tectonic plates

Explanation:

7 0
4 years ago
Comparing Wave A (black) to Wave B (green), Wave A has a
Gennadij [26K]
I think it's C, longer wave length.
7 0
4 years ago
Read 2 more answers
Two balls collide head-on on a table. The first ball has a mass of 0.50 kg and an initial velocity of 12.0 m/s. The second ball
Gnom [1K]
A is correct according to below calculation.
m₁v₀₁+m₂v₀₂=m₁v₁+m₂v₂
((m₁v₀₁+m₂v₀₂)-m₁v₁)/m₂=v₂
v₂=((.5*12-.75*16)+(.5*21.6))/.75
v₂=6.4 m/s
4 0
3 years ago
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