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masha68 [24]
2 years ago
9

Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if

not 100% chance, that SOMEWHERE there is another earth, with another you, living the same life, at the same time. What are your thoughts about this??? that's so crazy to me
Physics
1 answer:
il63 [147K]2 years ago
7 0

Answer:

That insane it might be true because  a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.

Explanation:

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A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?
Talja [164]

Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

hope it helps :)

7 0
3 years ago
Why is the use of carbon- 14 dating limited?​
Vera_Pavlovna [14]

Answer:

because carbon 14 has only a short half life, rather than other elements with longer half lives.

Explanation:

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What is the formula to calculate acceleration​
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Explanation:

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3 years ago
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The variables _______ and ________ affect the gravitational force between objects.
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Mass................And........................Distance
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3 years ago
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A battery-operated car uses a 12.0-V system. Find the charge the batteries must be able to move in order to accelerate the 956kg
DiKsa [7]
<h2>Answer:</h2>

1.99 x 10⁶C

<h2>Explanation:</h2>

The electrical energy (E_{E}) stored in the battery will give the car some kinetic energy (E_{K}) which will cause the car to move from rest to some other point.

i.e

E_{E} = E_{K}                 ------------------(i)

<em>But;</em>

E_{E} =  \frac{1}{2} x Q x V;            -------------------(ii)

Where;

Q = charge on the battery

V = potential difference or voltage of the battery = 12.0V

<em>Also</em>

E_{K} = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)            -----------------(iii)

Where;

m = mass of the car = 956kg

v = final velocity of the car = 158m/s

u = initial velocity of the car = 0   [since the car starts from rest]

<em>Substitute equations (ii) and (iii) into equation (i) as follows;</em>

\frac{1}{2} x Q x V = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)       -----------------(iv)

<em>Substitute all necessary values into equation (iv) as follows;</em>

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (\frac{1}{2} x 956 x 0²)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (0)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²)

\frac{1}{2} x Q x 12.0 = 11932792

6Q = 11932792

<em>Solve for Q;</em>

Q =  11932792 / 6

Q = 1988798.67 C

Q = 1.99 x 10⁶C

Therefore, the amount of charge the batteries must have is 1.99 x 10⁶C

8 0
3 years ago
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