Answer:
18000 Bg
Explanation:
after 15 minutes = 36000/2
After 30 minutes = 36000/4
30 minutes × 2 = 1 hour
After 1 hour = 36000/4 × 2 = 18000 Bg
Answer:
Explanation:
Given that,
We have two capacitors connected in series
C1=2.0-μF
C2=4.0-μF
Then the equivalent of their series connection
1/Ceq = ½ + ¼
1/Ceq= (2+1)/4
1/Ceq=¾
Taking the reciprocal
Ceq= 4/3 μF
The capacitors are connected to a battery of 1kv
V=1000Volts
We know that,
Q=CV
Where Q is charge
C is capacitance and
V is voltage
Then, Q=4/3 ×1000
Q=4000/3 -μC
Since the capacitors are in series, then the charge pass through them, so each charge on the capacitors are 4000/3 μF
After the capacitor has been charge, the capacitor are disconnect and reconnected in parallel to each other,
For parallel connection, they have the same voltage but different charges.
When connected in parallel, there is a charge redistribution,
And the total charge will be 2•4000/3=8000/3 -μF
Then, Q1 +Q2= 8000/3 μF
Now the charge on each capacitor will be, let them have a common voltage V
Q=CV
Then, Q1=C1V
Q1= 2×V=2V
Q2= 4×V=4V
Then, Q1+Q2=8000/3
4V+2V=8000/3
6V=8000/3
V=8000/(3×6)
V=4000/9
V=444.44Volts
Now, Q1=2V
Q1=2×4000/9
Q1=8000/9 μF
Also, Q2=4V
Q2=4×4000/9
Q2=16000/9 μF
Answer:
The difference of power is
ΔP = 172.767 kPa
Explanation:
ρ = 1390 kg / m³
v = 9.63 m/s
d₁ = 10.1 cm , d₂ = 15.3 cm
Δz = 8.85 m
To find the difference ΔP between the fluid pressure at locations 2 and the fluid pressure at location 1
ΔP = ρ * g * Z + ¹/₂ * ρ * v² * ( 1 - (d₁ / d₂)⁴ )
ΔP = 1390 kg / m³ * 9.8 m/s² * 8.85 m + 0.5 * 1390 kg / m³ *(9.63 m /s)² * (1 - (0.101 m / 0.153 m )⁴ )
ΔP = 172.767 x 10 ³ Pa
ΔP = 172.767 kPa
The appropriate response is the Unusual climate. These are eccentric serious or unseasonal climate; climate at the extremes of the authentic circulation—the range that has been found before. Regularly, extraordinary occasions depend on an area's recorded climate history and characterized as lying in the most strange 10%.
