See the attached picture:
A car travels at 2000 meters east in 40 seconds. What is the cars velocity
1 answer:
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According to the given statement:
- The frequency response does not change, which is the first thing we notice.
- The new resistance at the resonance point causes a reduction in the circuit's current flow.
- Z = R + R₂
electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.
<h3>How does a series circuit operate?</h3>According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.
<h3>According to the given information:</h3>The impedance of a series circuit is
Z₀² = R² + (X-X
) ²
The initial resistance impedance shifts to when we add another resistor to the series
Z² = (R + R₂) ² + (X - X
) ²
Let's examine this sentence.
- The frequency response remains unchanged, which is the first thing we notice.
- The new resistance at the resonance point causes the circuit's current to decrease.
Z = R + R₂
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Answer:
The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²
The shear stress at a distance 0.5-in away from the pipe wall is 0
Explanation:
Given;
pressure drop per unit length of pipe = 0.6 psi/ft
length of the pipe = 12 feet
diameter of the pipe = 1 -in
Pressure drop per unit length in a circular pipe is given as;
make shear stress (τ) the subject of the formula
Where;
τ is the shear stress on the pipe wall.
ΔP is the pressure drop
L is the length of the pipe
r is the distance from the pipe wall
Part (a) shear stress at a distance of 0.3-in away from the pipe wall
Radius of the pipe = 0.5 -in
r = 0.5 - 0.3 = 0.2-in = 0.0167 ft
ΔP = 0.6 psi/ft
ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²
Part (b) shear stress at a distance of 0.5-in away from the pipe wall
r = 0.5 - 0.5 = 0