If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.
Given,
Tension force in the rope is (T) = 160 N
Displacement of the skier (S) = 270 m
The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.
Therefore, work done by the rope on the skier is,
![W=T.S](https://tex.z-dn.net/?f=W%3DT.S)
⇒![W=270*160*cos\pi \\W=-43200 J](https://tex.z-dn.net/?f=W%3D270%2A160%2Acos%5Cpi%20%5C%5CW%3D-43200%20J)
Hence work done by the rope is - 43200 J.
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Answer:
c > √(2ab)
Explanation:
In this exercise we are asked to find the condition for c in such a way that the results have been real
The given equation is
½ a t² - c t + b = 0
we can see that this is a quadratic equation whose solution is
t = [c ±√(c² - 4 (½ a) b)] / 2
for the results to be real, the square root must be real, so the radicand must be greater than zero
c² -2a b > 0
c > √(2ab)
You could use a magnetic generator or you could use hydraulic power
The correct option is (D) Gamma (
![_0^0\gamma](https://tex.z-dn.net/?f=_0%5E0%5Cgamma)
)
Explanation:Now this question is a tricky one because all of these options are somehow involved in radioactive decay; however, in this case the SYMBOL is required NOT the elements. There are three symbols involved in radioactive decay, which are:
1. α for alpha decay
2. β for beta decay
3. γ for gamma decay
In the options only one symbol is present which is
gamma. Hence option (D) Gamma ( ![_0^0\gamma](https://tex.z-dn.net/?f=_0%5E0%5Cgamma)
) is the correct answer.
-i