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3 years ago

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Which waves move by replacing one particle with another

2 answers:

stiv31 [10]3 years ago

8 0

Question : Which waves move by replacing one particle with another

Answer : Sound waves

Why : Well because sound waves only work when music or a clip is playing. If you stop it stops completely and nothing else. If you replace one particle on a sound wave the sound is going to change depending on what type of particle you changed!

-procklown

sweet-ann [11.9K]3 years ago

4 0

It should be Sound waves

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Atoms with a low ionization energy hold tight to their outer valence electrons.

Anestetic [448]

True would be the Correct answer

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3 years ago

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A. 24.89<br> B. 25.89<br> C. 17.74<br> D. 19.73

Veronika [31]

Answer: D

Explanation:

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2 years ago

Glycerin (C3H8O3) is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 154 g of glycerin to 316 mL o

garri49 [273]

Answer:

$P_{sol}=50.4\ mm.Hg$

Explanation:

According to given:

molecular mass of glycerin, $M_g=3\times 12+8+3\times 16=92\ g.mol^{-1}$

molecular mass of water, $M_w=2+16=18\ g.mol^{-1}$

∵Density of water is $0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}$

∴mass of water in 316 mL, $m_w=316\times 0.992=313.5 g$

mass of glycerin, $m_g=154\ g$

pressure of mixture, $P_x=55.32\ torr= 55.32\ mm.Hg$

temperature of mixture, $T_x=40^{\circ}C$

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

<u>moles of water in the given quantity:</u>

$n_w=\frac{m_w}{M_w}$

$n_w=\frac{313.5}{18}$

$n_w=17.42 moles$

<u>moles of glycerin in the given quantity:</u>

$n_g=\frac{m_g}{M_g}$

$n_g=\frac{154}{92}$

$n_g=1.674 moles$

<u>Now the mole fraction of water:</u>

$X_w=\frac{n_w}{n_w+n_g}$

$X_w=\frac{17.42}{17.42+1.674}$

$X_w=0.912$

<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>

$\therefore P_{sol}=X_w\times P_x$

$\therefore P_{sol}=0.912\times 55.32$

$P_{sol}=50.4\ mm.Hg$

7 0

3 years ago

In this diagram, medium A represents water and medium B represents air. The phenomenon in this diagram, moving from A to B, is c

Readme [11.4K]

Its C) refraction
hope its may help you

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3 years ago

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A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated

Yakvenalex [24]

Answer:

Centripetal acceleration

Explanation:

The centripetal acceleration is the motion inwards towards the center of a circular path.

<em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path. </u></em>

That is;

ac = v²/r

Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m

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3 years ago