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2 years ago

Los números reales tienen un primer número?

Mathematics

1 answer:

Radda [10]2 years ago

8 0

Answer:

no, real numbers do not have first numbers.

Step-by-step explanation:

There are also more complicated number systems than the real numbers, such as the complex numbers. Every real number is a complex number, but not every complex number is a real number. Similarly, 3/7 is a rational number but not an integer.

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6. Given two numbers 8 and 5:<br> Write "the distance between 8 and 5" as a mathematical expression.

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Answer:

Step-by-step explanation:

5+3=8 and on a number line 5 and 8 and 3 numbers away

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2 years ago

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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1

Ratling [72]

Answer:

$\sqrt3$

Step-by-step explanation:

To find:

The value of $tan60^\circ$ = ?

Solution:

Kindly consider the equilateral $\triangle ABC$ as attached in the answer area.

Let the side of triangle = $a$ units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = $\frac{a}{2}$

Using Pythagorean Theorem in $\triangle ABD$ :

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

Side AD = $\frac{\sqrt3}{2}a$

Using Trigonometric ratio:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tanB = \dfrac{AD}{BD}$

Putting the values of AD and BD:

$tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}$

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2 years ago

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Do anybody play valorant?

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Step-by-step explanation:

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A scuba instructor wants to know the opinions of scuba divers about online scuba diving tests. She obtains a list of 900 scuba d

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Answer:

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3 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

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3 years ago