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weeeeeb [17]
2 years ago
5

A 500.0 g sample of aluminium, I initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature o

f 90.7 degrees. How much heat (in KJ) has been absorbed by the sample? To one decimal place
Specific heat= 0.9930j g-1 K-1 for aluminium
Chemistry
1 answer:
babunello [35]2 years ago
3 0
Q= (500.0)(0.9930)(90.7 - 25.0)
Q= 32620.05
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