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weeeeeb [17]
2 years ago
5

A 500.0 g sample of aluminium, I initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature o

f 90.7 degrees. How much heat (in KJ) has been absorbed by the sample? To one decimal place
Specific heat= 0.9930j g-1 K-1 for aluminium
Chemistry
1 answer:
babunello [35]2 years ago
3 0
Q= (500.0)(0.9930)(90.7 - 25.0)
Q= 32620.05
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A cylinder was charged with 1.25 atm of oxygen gas, 6.73 atm of argon, and 0.895 atm of xenon. What is the mole fraction of each
katrin2010 [14]

Considering the Dalton's partial pressure, the mole fraction of each gas is:

  • x_{oxygen}= 0.14
  • x_{argon}= 0.76
  • x_{xenon}= 0.10

<h3>Dalton's partial pressure</h3>

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

P_{T} =P_{1} +P_{2} +...+P_{n}

where n is the amount of gases in the gas mixture.

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

P_{A} =x_{A} P_{T}

In summary, the total pressure in a mixture of gases is equal to the sum of partial pressures of each gas.

Mole fraction of each gas

In this case, you know that:

  • P_{oxygen }= 1.25 atm
  • P_{argon}= 6.73 atm
  • P_{xenon}= 0.895 atm
  • P_{T} =P_{oxygen} +P_{argon}+P_{xenon}= 1.25 atm + 6.73 atm + 0.895 atm= 8.875 atm

Then:

  • P_{oxygen} =x_{oxygen} P_{T}
  • P_{argon} =x_{argon} P_{T}
  • P_{xenon} =x_{xenon} P_{T}

Substituting the corresponding values:

  • 1.25 atm= x_{oxygen} 8.875 atm
  • 6.73 atm= x_{argon} 8.875 atm
  • 0.895 atm= x_{xenon} 8.875 atm

Solving:

  • x_{oxygen}= 1.25 atm÷ 8.875 atm= 0.14
  • x_{argon}= 6.73 atm÷ 8.875 atm= 0.76
  • x_{xenon}= 0.895 atm÷ 8.875 atm=0.10

In summary, the mole fraction of each gas is:

  • x_{oxygen}= 0.14
  • x_{argon}= 0.76
  • x_{xenon}= 0.10

Learn more about Dalton's partial pressure:

brainly.com/question/14239096

brainly.com/question/25181467

brainly.com/question/14119417

#SPJ1

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2 years ago
Predict the bond polarity of the following bonds:
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How many milliliters of 0.50 M KOH are needed
spayn [35]

Answer:

Option D. 30 mL.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above,

The mole ratio of the acid, nA = 1

The mole ratio of the base, nB = 1

Step 2:

Data obtained from the question. This include the following:

Volume of base, KOH (Vb) =.?

Molarity of base, KOH (Mb) = 0.5M

Volume of acid, HNO3 (Va) = 10mL

Molarity of acid, HNO3 (Ma) = 1.5M

Step 3:

Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:

MaVa / MbVb = nA/nB

1.5 x 10 / 0.5 x Vb = 1

Cross multiply

0.5 x Vb = 1.5 x 10

Divide both side by 0.5

Vb = (1.5 x 10) /0.5

Vb = 30mL

Therefore, the volume of the base, KOH needed for the reaction is 30mL.

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I need help on this question
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B. I’m sorry if I’m wrong ! Wasn’t sure about this question .
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