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2 years ago

5

A 500.0 g sample of aluminium, I initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature o

f 90.7 degrees. How much heat (in KJ) has been absorbed by the sample? To one decimal place
Specific heat= 0.9930j g-1 K-1 for aluminium

1 answer:

babunello [35]2 years ago

3 0

Q= (500.0)(0.9930)(90.7 - 25.0)
Q= 32620.05

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