What is the average rate of change of the function f(x) = 5x ^ 2 + 20x between x = 0 and x = 0.5
1 answer:
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Answer:
22.5
Step-by-step explanation:
The average rate of change on the interval [a, b] is the ratio ...
(f(b) -f(x))/(b -a)
For your function and interval, it is ...
(f(0.5) -f(0))/(0.5 -0)
Since f(0) = 0, this reduces to ...
average rate of change = 2·f(0.5) = 2(5(0.5)² +20(0.5)) = 2(5/4 +10)
average rate of change = 22.5
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Answer:
Option 3 is right
z37 is between 2 and 3 standard deviations of the mean.
Step-by-step explanation:
Let X be a random variable which represents the mean number of miles that the employees in a department live from work
X is normal (N(29,3.6)
WE have to find Z score for X
Z =
=2.22
i.e. 37 is 2.22 std deviations from the mean.
In other words, z37 is between 2 and 3 standard deviations of the mean.