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notka56 [123]
3 years ago
7

What is the fancy psychological term for "mental process"?

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

cognition

Explanation:

give me brainliest pls

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A scientist finds an organism that cannot move. It has many cells and get food from its environment. In which Kingdom does it
Allisa [31]
An organism that does not move on its own and makes food from its environment is a producer.
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3 years ago
What affects the rates of reactions? describe each. <br> a. <br> b.?
Anvisha [2.4K]
Rates can be calculated with Arrhenius equation k = Axe^(-Ea/RT)
a. temperature affects the rate - imagine you are making coffee, so coffee crystals are boiled faster on higher temperature. Simplified but makes sense.
b. Ea is activation energy. Imagine, while preparing coffee, some of ingredients change to a different one, so there is a A -> B reaction (simplified). Now, Ea is energy barrier that stands on the arrow of this reaction, preventing A to transform to B. If Ea is small, reaction will go easy (not fast!), if Ea is large –reaction will not happen so easy (you ll have to use catalyst for example)
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3 years ago
How does viscosity affect boiling point?
sveticcg [70]
D- viscosity has no effect on boiling point
8 0
3 years ago
Which statement is true about the speed of light
Sedbober [7]

Answer:

nothing can travel faster than light

In vacuum it is 186282 miles per second

Explanation:

5 0
3 years ago
What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3
ser-zykov [4K]

Answer : The density of air in lbm/ft^3 and kg/m^3 is, 0.0743lbm/ft^3 and 1.19kg/m^3 respectively.

Explanation :

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

^oC=(75-32)\times \frac{5}{9}=24^oC

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273+^oC

K=273+24=297K

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

\rho = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

\rho=\frac{PM}{RT}

\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}

\rho=1.19g/L

Now we have to calculate density in lbm/ft^3.

Conversion used :

1g/L=0.0624lbm/ft^3

So,

1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3

The density of air in lbm/ft^3 is, 0.0743lbm/ft^3

Now we have to calculate density in kg/m^3.

Conversion used :

1g/L=1kg/m^3

So,

1.19g/L=1.19kg/m^3

The density of air in kg/m^3 is, 1.19kg/m^3

8 0
3 years ago
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