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Trava [24]
3 years ago
11

Why are alphabets in the order they are?

Chemistry
1 answer:
sineoko [7]3 years ago
4 0
Its arbitrary. It was developed on the greek phoenetic system and never reallybwas explained.
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Mademuasel [1]
Answer: true
sound waves need particles to move through
6 0
2 years ago
Read 2 more answers
Write the structure of the ionized form of phenylalanine
Licemer1 [7]
Amino Acids undergo a kind of acid base reaction within a molecule. The Amino group acts as a base and accepts proton from Carboxylic functional group resulting in formation of Ammonium with positive charge and a negative charge on Carboxylate. Such molecules containing both positive and negative charges are called as Zwittor Ions. Phenylalanine both in Un-ionized and Ionized form is shown below,

7 0
3 years ago
A major textile dye manufacturer developed new yellow dye. The dye has a percent composition of 75.9 5% C, 17.72% N
AnnZ [28]

Answer:

Such molecule must have molecular formula of C15N3H15

Explanation:

Mass of carbon in such molecule

0.7595*240_{g/mol} =182.28_{g C/mol}

The atomic mass of carbon is 12.01 g/mol, so in 182.28 g of carbon there is 15.18 mols of carbon.

Mass of Nitrogen in such molecule

0.1772*240_{g/mol} =37.73_{g C/mol}

The atomic mass of nitrogen is 14.01 g/mol, so in 42.53g of nitrogen there is 3.04 mols of nitrogen.

Mass of Hydrogen in such molecule

0.0633*240_{g/mol} =15.19 {g C/mol}

The atomic mass of Hydrogen is 1.00 g/mol, so in 15.19 g of Hydrogen there is 15.19 mols of Hydrogen.

Such molecule must have molecular formula of C15N3H15

5 0
3 years ago
Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi
VLD [36.1K]

The  volume of the new solution is

calculation

by use of the formula

M1V1= M2V2

M1 (molarity 1)  = 2.13 M

V1 (volume 1) = 1.24 l

M2 ( molarity 2) = 1.60 M

V2 (volume 2) = ?

by making V2 the subject of the formula

V2 = M1 V1/ M2

V2=( 1.24  x 2.13)÷ 1.60=  1.651 L

5 0
3 years ago
A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base
yawa3891 [41]

Answer:

11.39

Explanation:

Given that:

pK_{b}=4.82

K_{b}=10^{-4.82}=1.5136\times 10^{-5}

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.805\ g}{82.0343\ g/mol}

Moles= 0.022\ moles

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.022}{0.055}

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

At t =equilibrium     (0.4-x)                        x           x            

The expression for dissociation constant is:

K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}

1.5136\times 10^{-5}=\frac {x^2}{0.4-x}

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³  M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

<u>pH = 14 - pOH = 14 - 2.61 = 11.39</u>

5 0
3 years ago
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