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3 years ago

Find the value of x for which the lines p and q are parallel.

Mathematics

2 answers:

madreJ [45]3 years ago

7 0

Answer:

Step-by-step explanation:

have a good day

nydimaria [60]3 years ago

6 0

Answer:

D) 7

Step-by-step explanation:

Since the two angles marked are corresponding, if $p$ and $q$ are parallel, they must be equal.

Therefore, we have:

$14x+18=116,\\14x=98,\\x=\boxed{7}$

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19. You roll two standard number cubes. What is the probability that the sum is odd, given than one of the number cubes shows a

In-s [12.5K]

6 numbers per cube

if one is a 1, then the other one has to be a 2, 4 or 6 to be an odd sum

1+2=3, 1+4=5,1+6=7

since there are 3 numbers you can get that would be a 3/6 ( reduce to 1/2) probability

so 1/2 probability

5 0

3 years ago

Read 2 more answers

Determine whether the statement is true or false.

amid [387]

Answer:

False

Step-by-step explanation:

1/3^4=3^4

0.012346≠81

False

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3 years ago

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Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago

-3x+4y=12 and 1/4x - 1/3y =1

zavuch27 [327]

Answer:

Step-by-step explanation:

-3x + 4y = 12

12(1/4x - 1/3y = 1)

-3x + 4y = 12

3x - 4y = 12

there is no solution

5 0

3 years ago

L Factor the greatest common factor (GCF) from each polynomial. 10n^3 - 35n^2+25n

Maru [420]

Answer:

5n(2n^2-7n+5)

Step-by-step explanation:

4 0

2 years ago