Answer:
<u>The cube root parent function:</u>
- f(x) =
![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
<u>Horizontally stretched by a factor of 4:</u>
- g(x) → f(1/4x) =
![\sqrt[3]{1/4x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%7D)
<u>Translated 5 units right:</u>
- h(x) → g(x - 5) =
![\sqrt[3]{1/4x - 5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20-%205%7D)
<u>Translated 3 units up:</u>
- k(x) → h(x) + 3 =
![\sqrt[3]{1/4x - 5} + 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20-%205%7D%20%2B%203)
A rational number because any number between two integers is a fraction.
Answer:
The dimension of the base of the Rectangle Pyramid is Length = 10 and Width = 8/3
Step-by-step explanation:
Given
Rectangle Pyramid
Base Length = 3x + 1
Base Width = x
Height = 12
Volume = 96
Required
Dimension of the base of the pyramid
Given that the volume of the pyramid is ⅓ of the base area * the height.
This is represented mathematical as
Volume = ⅓ * base area * height.
Where
Base area = width * length
Base area = (3x + 1) * x
Base area = 3x² + x.
So,
Volume becomes
Volume = ⅓ * (3x² + x) * 12.
Volume = (3x² + x) * 4
Substitute 96 for volume
96 = (3x² + x) * 4
Divide both sides by 4
96/4 = (3x² + x) * 4/4
24 = 3x² + x
Subtract 24 fr both sides
24 - 24 = 3x² + x - 24
0 = 3x² + x - 24
3x² + x - 24 = 0
Expand
3x² + 9x - 8x - 24 = 0
Factorize
3x(x + 3) - 8(x + 3) = 0
(3x - 8)(x + 3) = 0
3x - 8 = 0 or x + 3 = 0
3x = 8 or x = -3
x = 8/3 or x = -3
Recall that
Length = 3x + 1
Width = x
For any of the above expression, x can't be less than 0; so, x = -3 can't be considered.
Substitute x = 8/3
Length = 3x + 1
Length = 3(8/3) + 1
Length = 8 + 1
Length = 9
Width = x
Width = 8/3
Hence, the dimension of the base of the Rectangle Pyramid is Length = 10 and Width = 8/3
Answer:
angle 4
Step-by-step explanation:
8x^2-5x-2
method
open bracket
6x^2-2x-3+x^2-3x+1
collect like terms
6x^2+2x^2-3-3x+1
8x^2-3-3x+1
again collect like terms
8x^2-2x-3x-3+1
8x^2-5x-3+1. (-×-=+ addition but keeping sign minus
8x-5x-2. (-×+=-)
