Answer:
a + b ≥ 40
a + 5 ≤ b
2.50a + 1.50b ≤ 105
Step-by-step explanation:
We are told she would like to have at least 40 cupcakes and cookies combined.
If a is number of cupcakes and b is number of cookies, then this inequality is;
a + b ≥ 40
Secondly, we are told she would like to have at most 5 more cupcakes than cookies.
Thus, the inequality is;
a + 5 ≤ b
Lastly, we are told that cupcakes sell for $2.50 and cookies for $1.50
Thus, the inequality is;
2.50a + 1.50b ≤ 105
Finally, the 3 inequalities are;
a + b ≥ 40
a + 5 ≤ b
2.50a + 1.50b ≤ 105
Answer would be 9/6,but can be simplified to 3/2
7 + (-3x^2) for x = 0 7 + [-3(0)^2]; = 7 + -3(0); = 7 - 0; = 7
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
