Question

A spinner has 6 equally divided sections labeled A, B, C, D, E and F. After spinning the spinner, a number cube is rolled. What is the probability that the spinner will land on a consonant and the number cube will land on a number greater than 2?

Answer 1

Answer: $\dfrac{2}{9}$

Step-by-step explanation:

Given

The spinner has 6 equal sections A, B, C, D, E, and F

The two events occurred one after the other. So, the probability is the product of the probabilities of each event.

There are two consonants in the given 6 letter

The probability of landing over a consonant  is

$P_1=\dfrac{2}{6}$

The number greater than 2 in a cube are 3,4,5,6

So, probability corresponding to it

$P_2=\dfrac{4}{6}$

So, the required probability is

$\Rightarrow P=P_1\times P_2\\\Rightarrow P=\dfrac{2}{6}\times \dfrac{4}{6}\\\\\Rightarrow P=\dfrac{8}{36}\\\\\Rightarrow P=\dfrac{2}{9}$