1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timama [110]
3 years ago
15

Calculate the density of an objects whose mass is 93.2 g and its volume is 4.67​

Chemistry
2 answers:
Masteriza [31]3 years ago
6 0
To find the density, the formula would be d= m/V. Your answer would be 19.9 or if you round, 20.
Vsevolod [243]3 years ago
3 0

Answer:

19.9571734475

Explanation:

Mass/Volume= Density

You might be interested in
What is 1 mole of neon gas
iragen [17]
The mass of one mole of Neon is equal to the molar mass depicted on the periodic table. This is <span>20.1797 g.</span>
6 0
3 years ago
Read 2 more answers
The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
Alenkinab [10]

Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

Enthaply of combustion of benzoic acid = 3,228 kJ/mol  

Mass of benzoic acid = 0.590 g

Moles of benzoic acid = \frac{0.590 g}{122.12 g/mol}=0.004831 mol

Energy released by 0.004831 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J

Heat capacity of the calorimeter = C  

Change in temperature of the calorimeter = ΔT = 2.125°C

Q=C\times \Delta T

15,595.5 J=C\times 2.125^oC

C=7,339.05 J/^oC

Heat released on combustion of Glucose: :

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=1.400 g

Moles of glucose =\frac{1.400 g}{180.16 g/mol}=0.007771 mol

Energy released by the 0.007771 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

21,603.01 J=7,339.05 J/^oC\times \Delta T'

\Delta T'=2.943^oC

2.943 °C temperature change from the combustion of the glucose has been taken place.

8 0
3 years ago
6. Macromolecules represent which level of organization in the body?
hodyreva [135]

Answer:

Chemical

Explanation:

Macromolecules are part of the chemical components of cells. For example, DNA, proteins, and lipids.

Cells of similar types/function form tissues. Different types of tissues interact together to form organs. Organs form a common function.

6 0
3 years ago
When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?A. 2.B. 4.C. 8.D. Unkno
babymother [125]

Answer:

Option B.

Explanation:

As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:

2C₂H₆  +  7O₂   →   4CO₂  +  6H₂O

So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.

Then 2 moles of ethane will produce 4 moles of CO₂

6 0
3 years ago
In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
Other questions:
  • Carbon Monoxide reacts with steam to produce carbon dioxide and hydrogen. At 700K, the equilibrium constant is 5.10. Calculate t
    5·1 answer
  • Which term describes a section of Earht's structure below moving continents as parts of large plates?
    11·1 answer
  • How the heck do i do this
    5·1 answer
  • Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
    9·1 answer
  • Rank the following carboxylic acids by acid strength, with the strongest at the top and the weakest at the bottom. It may help t
    6·1 answer
  • Which of the following hydrocarbons will be the most acidic?
    10·1 answer
  • 4. What is the common name of the compound CaOCI,?​
    11·1 answer
  • 2 Zn + 2HNO2-&gt; 2 ZN(NO2)2 + H2
    15·1 answer
  • system of equations You and your friend are making 30 liters of sodium water. You have liters of 10% sodium and your friend has
    8·1 answer
  • 10. How many molecules are contained in 5.6 L of H2 at STP?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!