The mass of one mole of Neon is equal to the molar mass depicted on the periodic table. This is <span>20.1797 g.</span>
Answer:
2.943 °C temperature change from the combustion of the glucose has been taken place.
Explanation:
Heat released on combustion of Benzoic acid; :
Enthaply of combustion of benzoic acid = 3,228 kJ/mol
Mass of benzoic acid = 0.590 g
Moles of benzoic acid = 
Energy released by 0.004831 moles of benzoic acid on combustion:

Heat capacity of the calorimeter = C
Change in temperature of the calorimeter = ΔT = 2.125°C



Heat released on combustion of Glucose: :
Enthaply of combustion of glucose= 2,780 kJ/mol.
Mass of glucose=1.400 g
Moles of glucose =
Energy released by the 0.007771 moles of calorimeter combustion:

Heat capacity of the calorimeter = C (calculated above)
Change in temperature of the calorimeter on combustion of glucose = ΔT'



2.943 °C temperature change from the combustion of the glucose has been taken place.
Answer:
Chemical
Explanation:
Macromolecules are part of the chemical components of cells. For example, DNA, proteins, and lipids.
Cells of similar types/function form tissues. Different types of tissues interact together to form organs. Organs form a common function.
Answer:
Option B.
Explanation:
As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.
Then 2 moles of ethane will produce 4 moles of CO₂
Answer: The given statement is TRUE.
Explanation:
An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.
Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.
For example for the given equilibrium reaction;

![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.