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xz_007 [3.2K]
2 years ago
7

The industrial preparation of ozone (03) uses oxygen gas (O2), as shown in the equation below. 302(8) electricity 203(g) A If 96

.0 kg of O2 gas actually yields 11.5 kg of 03. what is the percent yield in this reaction? A. 3.10% B. 8.35% C. 12.0% D. 18.0% ​
Chemistry
1 answer:
Paul [167]2 years ago
5 0

The percent yield of the industrial preparation of ozone is the 12%.

<h3>How do we calculate the percent yield?</h3>

Percent yield of any reaction will be calculated by using the below equation:

% yield = (Actual yield / Theoretical yield) × 100%

Given chemical reaction is:

3O₂(g) → 2O₃(g)

Moles of oxygen will be calculated as:

n = W/M, where

  • W = given mass = 96kg = 96,000g
  • M = molar mass = 32g/mol

n = 96,000/32 = 3000mol

From the stoichiometry of the reaction it is clear that:

3 moles of oxygen = produces 2 moles of ozone

3000 moles of oxygen = produces 2/3(3000)=2000 moles of ozone

Mass of 2000 moles of ozone = (2000mol)(48g/mol) = 96,000g = 96kg

Actual yield of ozone = 11.5kg (given)

Now percent yield will be calculated as:

% yield = (11.5 / 96) × 100% = 11.97% = 12%

Hence required percent yield is 12%.

To know more about percent yield, visit the below link:

brainly.com/question/20349874

#SPJ1

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8. Sulfur has a first ionization energy of 1000 kJ/mol. Photons of what frequency are required to ionize one mole of Sulfur?​
Lynna [10]

Answer:

the frequency of photons v = 1.509\times10^{39}Hz

Explanation:

Given:  first ionization energy of 1000 kJ/mol.

No. of moles of sulfur = 1 mole

\Delta E_1 = 1000KJ/mol

We know that plank's constant

h = 6.626\times10^{-34} Js

Let the frequency of photons be ν

Also we know that ΔE = hν

this implies ν = ΔE/h

= \frac{10^6J}{6.626\times10^{-34} Js}

v = 1.509\times10^{39}Hz

Hence, the frequency of photons v = 1.509\times10^{39}Hz

6 0
3 years ago
How to calculate moles
blondinia [14]

Explanation:

First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.

For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

8 0
3 years ago
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What's is the mass of 0.500 mol NH3​
Setler [38]

Answer:

8.5155g NH3

Explanation:

the molar mass of NH3​ is 17.031 g/mol

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4 0
3 years ago
HURRY PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!
aivan3 [116]

Answer:


When <em>a scientist on Earth drops a hammer and a feather at the same time an astronaut on the moon drops a hammer and a feather, the result</em>  expected is that <em>the hammer hits the ground before the feather on Earth, and the hammer and feather hit at the same time on the moon (option D).</em>


Explanation:


In the abscence of atmosphere (vacuum), the objects fall in free fall. This is, the only force acting on the objects is the gravitational pull, which is directed vertlcally downward.


Under such absecence of air, the equations that rules the motion are:


  • V = Vo + gt
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As you see, all those equations are independent of the mass and shape of the object. This explains why <em>when an astronaut on the moon drops a hammer and a feather at the same time</em>, <em>the hammer and feather hit at the same time on the moon</em>, a space body where the gravitational attraction is so small (approximately 1/6 of the gravitational acceleration on Earth) that does not retain atmosphere.


On the other hand, the air (atmosphere) present in Earth  will exert a considerable drag force on the feather (given its shape and small mass), slowing it down, whereas, the effect of the air on the hammer is almost neglectable. In general and as an approximation, the motion of the heavy bodies that fall near the surface is ruled by the free fall equations shown above, so, <em>the result </em>that is<em> expected  when a scientist on Earth drops a hammer and a feather at the same time is that the hammer hits the ground before the feather</em>.

8 0
3 years ago
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Several properties of water are shown. Classify each property as a physical property or a chemical property.
34kurt

Chemical property:

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Physical property:

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7 0
2 years ago
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