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3 years ago

What is photosynthesis??

Physics

2 answers:

fgiga [73]3 years ago

8 0

Answer:

The process in which green plants prepare their food in their body by using carbon dioxide and water in the presence of sunlight is called photosynthesis .

Hope it is helpful to you ☺️

Korolek [52]3 years ago

7 0

Explanation:

<h3>The process in which green plants prepare their food in their body by using carbon dioxide and water in the presence of sunlight is called photosynthesis.</h3>

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Submit your report about the four different lobes in the brain. Remember to proofread your work before submitting. PLEASE I NEED

dsp73

Answer:

The four lobes of the brain are the frontal, parietal, temporal, and occipital lobes.The frontal lobe is located in the forward part of the brain, extending back to a fissure known as the central sulcus. The frontal lobe is involved in reasoning, motor control, emotion, and language.

Explanation:

3 0

3 years ago

A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

4 0

4 years ago

A rocket accelerates at 25m/s^2 for 5s before it runs out of fuel and dies. What is the maximum height reached by the rocket?

sineoko [7]

Answer:

1109m

Explanation:

The distance h₁ traveled by the rocket during acceleration:

$h_1=\frac{1}{2}at^2$

The velocity v₁ at this height h₁:

$v_1=at$

When the rocket runs out of fuel, energy is conserved:

$E=\frac{1}{2}mv_1^2+mgh_1=mgh_2$

Solving for h₂:

$h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2$

8 0

3 years ago

An athlete produced 840 watts of power in 0.6 seconds. How much work did this individual perform during the exercise

Veseljchak [2.6K]

An athlete produced 840 watts of power in 0.6 seconds. And will produce 504 joule of work did this individual perform during the exercise.

<u>Solution:</u>

we know that power is the work done completed in a given interval of time.

Power = $\frac{work}{time}$

also, Work = Power × Time

Work = 840 × 0.6 = 504 joule

What is Power?

The quantity of work that can be accomplished in a certain amount of time is measured by power.
Power is expressed in joules per second (J/s) this is because work is denoted by the symbol J and time by the symbol s.
This is the watt, which is also known as the power unit in SI (W). One joule of labor per second is equal to one watt.
The number of watts that a device uses is indicated on labels for lightbulbs and other small appliances like microwaves.
A force must be applied in order for work to be completed, and there must also be motion or displacement in the force's direction.
The amount of force multiplied by the distance moved in the force's direction is known as the work done by a force acting on an item. Work has no direction and only magnitude. Work is a scalar quantity as a result.

Know more about work power numerical brainly.com/question/181496

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7 0

2 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$