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REY [17]
4 years ago
10

What's the difference between a wavelength and an an amplitude?

Physics
2 answers:
erastova [34]4 years ago
7 0
A wave is propagated by a point or a particle in a medium that vibrates or oscillates between its mean position and a maximum displacement position.

<u>Amplitude is the maximum displacement from the mean position.</u>

Due to the vibration of the particle, neighbouring particles get disturbed and they also oscillate but some small time (phase) behind.

Along the direction of propagation of the wave, the wave travels a wavelength distance in the same time that is taken by a particle to complete one oscillation.
It is the<u> distance between two successive crests (</u>maximum displacement positions - When a snap shot of wave is taken at one point of time.

valkas [14]4 years ago
3 0
Wavelength - the distance from one wave crest or trough to another wave crest or trough. Amplitude - the distance from the median point or "middle" of the wave straight up to a crest (a maximum) or straight down to a trough (or minimum), which is the peak amplitude; or the distance from a trough straight up to a crest, or a crest straight down to a trough, called peak-to-peak amplitude.
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Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
The phases of the moon depend on how much of the lighted side of the moon can be seen from Earth.
Ostrovityanka [42]

Answer:

true

Explanation:

if there is no light it's different from when there is

3 0
4 years ago
Give two reasons why circular water waves decrease in amplitude
Ronch [10]
1. friction between water molecules
2. the wave spreads out onto a larger and larger area, so per unit area, the energy of the wave goes down
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3 years ago
Please help with physics 2 part question giving 50 points
AveGali [126]

Answer:

2.88×10⁻⁹ s

2.40×10¹⁵ m/s²

Explanation:

Given:

v₀ = 12300 m/s

v = 6.92×10⁶ m/s

Δx = 0.997 cm = 0.00997 m

Part 1) Find: t

Δx = ½ (v + v₀)t

0.00997 m = ½ (6.92×10⁶ m/s + 12300 m/s) t

t = 2.88×10⁻⁹ s

Part 2) Find: a

(6.92×10⁶ m/s)² = (12300 m/s)² + 2a (0.00997 m)

a = 2.40×10¹⁵ m/s²

5 0
3 years ago
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