Answer:
3.28 cm
Explanation:
To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:
r = 
Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.
The mass and charge of a proton are:
m = 1.67 * 10^-27 kg
q = 1.6 * 10^-19 C
So, we get that the radius r will be:
r =
= 0.0328 m, or 3.28 cm.
Answer:
true
Explanation:
if there is no light it's different from when there is
1. friction between water molecules
2. the wave spreads out onto a larger and larger area, so per unit area, the energy of the wave goes down
FOLLOW ME FOR CLEARING YOUR NEXT DOUBT
Answer:
2.88×10⁻⁹ s
2.40×10¹⁵ m/s²
Explanation:
Given:
v₀ = 12300 m/s
v = 6.92×10⁶ m/s
Δx = 0.997 cm = 0.00997 m
Part 1) Find: t
Δx = ½ (v + v₀)t
0.00997 m = ½ (6.92×10⁶ m/s + 12300 m/s) t
t = 2.88×10⁻⁹ s
Part 2) Find: a
(6.92×10⁶ m/s)² = (12300 m/s)² + 2a (0.00997 m)
a = 2.40×10¹⁵ m/s²