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ad-work [718]
2 years ago
8

The table above lists the wavelength range, frequency range, possible uses, and hazards of the seven types of electromagnetic ra

diation. Which type of radiation helps doctors image the interior of the human body but also causes cell damage?
A.
microwave
B.
infrared
C.
radio wave
D.
X-ray
Physics
1 answer:
m_a_m_a [10]2 years ago
6 0
I think it's D caz X-ray scans can diagnose possibly life-threatening conditions such as blocked blood vessels, bone cancer, and infections. However, x-rays produce ionizing radiation—a form of radiation that has the potential to harm living tissue. However, the risk of developing cancer from radiation exposure is generally small.
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Thiết bị nào sau đây không phải là nguồn điện
kumpel [21]

Thiết bị không phải nguồn điện:

Đáp án D

7 0
3 years ago
A projectile is launched at a 30° angle relative to the
maksim [4K]

Answer:

The answer is 56

Explanation:

6 0
3 years ago
Read 2 more answers
It takes a car traveling at 18 m/s, 240 seconds to reach Chick-Fil-A from the school. Determine how far Chick-Fil-A is from the
777dan777 [17]

Answer:

The requested distance is 4320 meters

Explanation:

We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:

v=\frac{distance}{time}

Since we know the velocity and the time, we can solve for the distance:

\neq v=\frac{distance}{time} \\18\,\frac{m}{s}  = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m

8 0
3 years ago
A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the a
finlep [7]

Solution :

Let $m_1=m_2=4$ kg

$u_1 = 5$ m/s

Let $v_1$ and $v_2$ are the speeds of the disk $m_1$ and $m_2$  after the collision.

So applying conservation of momentum in the y-direction,

$0=m_1 .v_1_y -m_2 .v_2_y $

$v_1_y = v_2_y$

$v_1 . \sin 60=v_2. \sin 30$

$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$

$v_2=1.732 \times v_1$

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

$m_1.u_1=m_1.v_1_x+m_2.v_2_x$

$u_1=v_1_x+v_2_x$

$5=v_1. \cos 60 + v_2 . \cos 30$

$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$

$v_1 = 2.50$ m/s

So, $v_2 = 1.732 \times 2.5$

          = 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

5 0
2 years ago
Two point charges, initially 2.0 cm apart, experience a 1.0 N force. If they are moved to a new separation of 0.25 cm, what is t
den301095 [7]

Explanation:

Th electric force between charges is inversely proportional to the square of distance between them. It means,

F\propto \dfrac{1}{r^2}

Initial distance, r₁ = 2 cm

Final distance, r₂ = 0.25 cm

Initial force, F₁ = 1 N    

We need to find the electric force between charges if the new separation of 0.25 cm. So,

\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N

So, the new force is 64 N if the separation between charges is 64 N.

7 0
3 years ago
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