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2 years ago

Please tell me the correct answer and I will mark you brainliest

Mathematics

1 answer:

RoseWind [281]2 years ago

8 0

All of the answers you put are correct. good job!

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4x + x - 3-9 + 4x = 6 ??

Nookie1986 [14]

Answer:

$x=2$

Step-by-step explanation:

-------------------------

Given:

$4x+x-3-9+4x=6$

---------->>>>

Combine like terms.

$9x-12=6$

---------->>>>

Add 12 to both sides.

$9x=18$

---------->>>>

Divide both sides by 9.

$x=2$

-------------------------

Hope this is helpful.

8 0

2 years ago

What is 0.2 as a percent?

kumpel [21]

it would be 20% if 0.2 omg

5 0

2 years ago

Read 2 more answers

The expression 1.01 ⋅ 1.00 5 t 1.01⋅1.005 t 1, point, 01, dot, 1, point, 005, start superscript, t, end superscript gives the am

Nadya [2.5K]

Answer:

Step-by-step explanation:

The expression 1.01-1.005 gives the amount of money, in thousands of dollars, in Carter's savings account t years after he opens it What does 1.01 represent in this expression? Choose 1 answer Carter opened the savings account I year ago ⓢ Carter's savings account had $1,010 in it when he opened it. The amount of money in Carter's savings account increase by 1% each year.

1.01 ( 1.005 )^t

standard exponential equation is

y = a (b)^x

where a = initial value

comparing the two equations

we get

a = 1.01

so, it means 1.01 means Carters saving account had $ 1010 in it when it opened

6 0

2 years ago

Find the product of 4h(6ah)<br><br> please tell the correct answer:

svlad2 [7]

Answer:

24a $h^{2}$

Step-by-step explanation:

4 0

2 years ago

How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4)

saveliy_v [14]

<h3>Solution:</h3>

$\rightarrow\sf((p(x) {x}^{2} + 2x + 4)( {x}^{2} + 2x + 4)) \\ = \sf {ax}^{2} + bx + c \\ = \sf(p(x) {x}^{2} {x}^{2} + p(x) {x}^{2} (2x) + p(x) {x}^{2} \times 4 + 2x \times {x}^{2} + 2x(2x) + 2x \times 4 + {4x}^{2} + 4(2x) + 4 \times 4) \\ = \sf( {x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

<h3>Answer:</h3>

$\large\boxed{\sf{\red{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

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5 0

2 years ago