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juin [17]
3 years ago
6

PLEASE HELP

Chemistry
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

A. Melting point

Explanation:

Isotopes have the same atomic number hence the same number of electrons which causes them to have the same chemical properties. But isotopes have different number of neutrons which causes them to have different mass numbers. The difference in mass numbers causes isotopes to have different physical properties. Heavier isotopes have a higher mass numbers than lighter isotopes because of which they have a higher melting point, boiling point etc.

Deffense [45]3 years ago
3 0

The answer is A. Isotopes only differ in the number of neutrons in the nucleus of their atoms. Otherwise, all other subatomic particles are the same. The isotope with the more neutrons in its nucleus is therefore, heavier (have higher mass number). They share the same chemical properties but have slight physical differences such as boiling points with the heavier element having a slightly higher boiling point that the lighter element.

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Answer : Option A) The direction the wire moves in


and Option C) the direction of the magnetic field.


Explanation : The direction of current flowing through the wire mainly depens on two factors which are i) direction of the wire moves in and ii) the direction of magnetic field.


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6 0
3 years ago
Calculate ΔH∘f for NO(g) at 435 K, assuming that the heat capacities of reactants and products are constant over the temperature
weeeeeb [17]

Answer:

91383 J

Explanation:

The equation of the reaction can be represented as:

\frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}     ------>NO_{(g)}

Given that:

The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.

The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

where:

\delta H^0__{R} = enthalpy of reaction

{\delta C_p(T')} = the difference in the heat capacities of the products and the reactants.

∴

\delta H^0__{R,435K} = \delta H^0__{R,298.15K} + \int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'

= 1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'

= 91300 J + (0.605 J.K⁻¹)(435-298.15)K

= 91382.79 J

\delta H^0__{R,435K} ≅ 91383 J

6 0
3 years ago
What weight of sodium hydroxide will react with 73 gram of hydrogen chloride gas at NTP to Produce 117.0 gram of Nacl and 36 gra
Wewaii [24]

Let's write the equation

\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}

According to law of conservation of mass .

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8 0
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