Answer:
See the answer below
Explanation:
The stock solution of Gentamycin has a concentration of 5 mg/ml while each plate needs to contain 50 micrograms/ml of Gentamycin.
5 mg/ml = 5000 micrograms/ml
There is a need to dilute the stock antibiotic solution in order to arrive at 50 micrograms/ml. Using the dilution principle;
m1v1 = m2v2
5000 x 1 = 50 x v2
v2 = 5000/50 = 1000 ml
<em>Hence, in order to prepare 50 micrograms/ml, 1 ml of the stock Gentamycin should be taken and diluted with 999 ml of distilled sterilized water. 1 ml of the diluted Gentamycin will then be added to each agar plate while they are still in the molten form at a warm temperature.</em>
The answer is B because the humoral immune response is mediated by antibody
Answer:
1. Cinder cones
2. All of these
Explanation:
1. Cinder cones develop from explosive eruptions of mafic (heavy, dark ferromagnesian) and intermediate lavas and are often found along the flanks of shield volcanoes. The outside of the cone is often inclined at about 30°, the angle of repose (the slope at which the loose cinder can stand in equilibrium).
2. Volcanic Explosivity Index (VEI) is a numeric scale that measures the relative explosivity of historic eruptions. Volume of products, eruption cloud height, and qualitative observations (using terms ranging from "gentle" to "mega-colossal") are used to determine the explosivity value. The Volcanic Explosivity Index (VEI) was derived to catalogue the explosive magnitude of historical eruptions, based on the order of magnitude of erupted mass, and gives a general indication as to the height the eruptive column reached.
Hope this helps!
Answer:
Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.
Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.
Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.
True true true true true true maybe
