2 years ago

How can you use the segment addition postulate to show that AE=AB+CD+DE

Mathematics

1 answer:

Anna71 [15]2 years ago

5 0

If the points B , C and D all lie on the line segment AE then AE = AB + CD + DE

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One angle of an isosceles triangle measures 110°. Which other angles could be in that isosceles triangle? Choose all that apply.

andre [41]

Answer:

Therefore the correct option is 2. 35 degree.

$\angle ABC=\angle ACB=35\°$

Step-by-step explanation:

Consider an Isosceles Triangle, Δ ABC where,

∠BAC = 110°

TO Find:

∠ ABC = ∠ACB = ?

Solution:

For an Isosceles Triangle

Base Angles are equal

∴ $\angle ABC=\angle ACB=x\ (say)$

Now,

Triangle sum property:

In a Triangle sum of the measures of all the angles of a triangle is 180°.

$\angle A+\angle B+\angle C=180\\\\110+x+x=180\\\therefore 2x=180-110=70\\\therefore x=\dfrac{70}{2}=35\°$

Therefore,

$\angle ABC=\angle ACB=35\°$

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A conical tent made of canvas has a base that is 34 feet across and a slant height of 12 feet to the nearest whole unit what is

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Check the picture below.

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\begin{cases}
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\end{cases}
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