How can you use the segment addition postulate to show that AE=AB+CD+DE
1 answer:
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First, lets sort the list from smallest to greatest. This will help with median, mode, and range.
4, 6, 10, 12, 12, 13, 16, 16, 16
Next, lets find the mean. Mean is found by adding all numbers up, then dividing them by the number of entries in the data set.
So the mean is 11.7.
Next, we'll find the median. The median is the value in the center of the list. Because there are 9 values, that means the center of the list is 5 with four numbers on each side of it. The 5th number in the list is 12, so that's our median.
Continuing, the mode is the number or numbers that appears the most often. For this data set, 16 appears 3 times while all other numbers appear 2 times or less. So, the mode is 16.
Lastly, the range is the difference between the largest number and the smallest number.
So the range is 12.
The second answer in the list matches all of these values, and is the correct solution.
4, 6, 10, 12, 12, 13, 16, 16, 16
Next, lets find the mean. Mean is found by adding all numbers up, then dividing them by the number of entries in the data set.
So the mean is 11.7.
Next, we'll find the median. The median is the value in the center of the list. Because there are 9 values, that means the center of the list is 5 with four numbers on each side of it. The 5th number in the list is 12, so that's our median.
Continuing, the mode is the number or numbers that appears the most often. For this data set, 16 appears 3 times while all other numbers appear 2 times or less. So, the mode is 16.
Lastly, the range is the difference between the largest number and the smallest number.
So the range is 12.
The second answer in the list matches all of these values, and is the correct solution.