Which form of energy is associated with the random motion of the particles in water

A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its

AleksAgata [21]

Answer:

$\delta=101.13 g/cm^3$

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

Six halves of atoms
Eight 1/8 of atom (1 in each corner)

In total:

$n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms$

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

$V_{cell}=L^3=(2.34e^{-8} cm)^3$

$V_{cell}=1.28*10^{-23}cm^3$

Atoms per cm3:

$n=\frac{4 atoms}{1.28*10^{-23}cm^3}$

$n=3.12*10^{23} atoms/cm^3$

Expressing in mass:

$\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol$

$\delta=101.13 g/cm^3$

6 0

3 years ago

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

UNO [17]

Answer:

See Explanation

Explanation:

Given

(a) to (d)

Required

Determine whether the given parameters can calculate the required parameter

To calculate either Density, Mass or Volume, we have

$Density = \frac{Mass}{Volume}$

$Mass = Density * Volume$

$Volume = \frac{Mass}{Density}$

(a) 432 g of table salt occupies 20.0 cm^3 of space

Here, we have:

$Mass = 432g$

$Volume = 20.0cm^3$

The above can be used to calculate Density as follows;

$Density = \frac{Mass}{Volume}$

$Density = \frac{432g}{20.0cm^3}$

$Density = 21.6g/cm^3$

(b) 5.00 g of balsa wood, density of balsa wood : 0.16 g/cm^3

Here, we have:

$Mass = 5.00g$

$Density = 0.16g/cm^3$

This can be used to solve for Volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{5.00g}{0.16g/cm^3}$

$Volume = 31.25cm^3$

(c) 32 cm^3 sample of gold density of 19.3 g/cm^3

Here, we have:

$Volume = 32cm^3$

$Density = 19.3g/cm^3$

This can be used to calculate Mass as follows:

$Mass = Density * Volume$

$Mass = 32cm^3 * 19.3g/cm^3$

$Mass = 617.6g$

(d) 150 g of iron, density of Iron = 79.0 g/cm^3

Here, we have

$Mass = 150g$

$Density = 79.0g/cm^3$

This can be used to calculate volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{150g}{79.0g/cm^3}$

$Volume = 1.90 cm^3$ Approximated

5 0

3 years ago

WILL MARK BRAINLIEST!!!! PLS HELP!!!

docker41 [41]

True

False

True

False

True

6 0

3 years ago

Chemistry problem. Is alcohol soluble in water?

stiv31 [10]

Alcohol is completely soluble in water in any amounts. That is because every alcohol contains carbon chain and OH group which are non-polar and polar. Any substances or solutes that will be mixed with the alcohol you will just get a simple solution.

5 0

3 years ago

A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio

____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

The units are mole fraction, molality and mass%

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = 59,0 moles of water

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = 0,0157

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = 0,889m

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = 16%

I hope it helps!

6 0

3 years ago