Based on the concentration of the solutions, the increase in volume is as follows:
- the volume of the 20% (m/v) starch increases
- the volume of the 10% (m/v) albumin increases
- the volume of the 5% (m/v) sucrose increases
<h3>What is osmosis?</h3>
Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.
The movement of water molecules in the solution pairs is as follows:
- the volume of the 20% (m/v) starch increases because water moves in from the 10% (m/v) starch solution.
- the volume of the 10% (m/v) albumin increases because water moves in from the 2% (m/v) albumin
- the volume of the 5% (m/v) sucrose increases because water moves in from the 0.5% (m/v) sucrose.
Therefore, the increase in volume depends on the concentration ofvthe solutions.
Learn more about osmosis at: brainly.com/question/2625460
Answer:
B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.
AND
C. The modern model explains all available data about atoms; Bohr’s model does not.
Explanation:
The answers are right on Edge. :)
Answer: 44g
Explanation: The formular for finding Moles is ;
Moles = Mass / Molar Mass or Formular Mass.
Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?
Making 'Formular Mass', subject of the formular; we thus have;
Formular mass = Mass / Moles = 440/ 10 = 44g
Answer:
Here's what I get
Explanation:
1. Nickel sulfate
base + acid ⟶ salt + water
NiSO₄ is a salt of the base Ni(OH)₂ and the acid sulfuric acid.
Hydroxides of transition metals are insoluble; most sulfates are soluble.
2. Carbonate + acid
Most carbonates are insoluble.
They react with acids to form carbonic acid (H₂CO₃), which decomposes into water and carbon dioxide.
Answer:
The average atomic weight = 121.7598 amu
Explanation:
The average atomic weight of natural occurring antimony can be calculated as follows :
To calculate the average atomic mass the percentage abundance must be converted to decimal.
121 Sb has a percentage abundance of 57.21%, the decimal format will be
57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .
123 Sb has a percentage abundance of 42.79%, the decimal format will be
42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .
Next step is multiplying the fractional abundance to it masses
121 Sb = 0.5721 × 120.904 = 69.169178400
123 Sb = 0.4279 × 122.904 = 52.590621600
The final step is adding the value to get the average atomic weight.
69.169178400 + 52.590621600 = 121.7598 amu
