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Eduardwww [97]
2 years ago
8

~Please help me out~

Mathematics
2 answers:
shtirl [24]2 years ago
8 0

Answer:

C) 54

And thanks I really needed it!

Oxana [17]2 years ago
4 0

Answer:

pretty sure the answer is C) 54

Step-by-step explanation:

I'm in 10th grade and I been in advanced math for my entire life

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Linear algebra is a fundamental component of continuum mechanics (and most engineering disciplines). Solve the following matrix
Mars2501 [29]

Answer:

A ) Not orthogonal to each other

B) 50i + 40j + 105k

C) The tensor product is attached below

D ) The value of X = F.X is attached below

Step-by-step explanation:

attached below is the detailed solution of the above problem

A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario  U.V = 4 hence they are not orthogonal to each other

b) The vector normal to plane is gotten by : U x V

= 50i + 40j + 105k

4 0
3 years ago
Based on the work shown on the left, what is the simplest form of StartRoot StartFraction 250 c cubed Over 9 d Superscript 6 Bas
Gnoma [55]

Answer:

It's A on E2020;  StartRoot StartFraction 250 c cubed Over 9 d Superscript 6 Baseline EndFraction EndRoot

Step-by-step explanation:

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6 0
3 years ago
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Write the first five terms of the sequence defined by the explicit formula
denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

a_n=21-2n^2

So to find the first five terms of this sequence, we will substitute the values of n (num here in the given formula:

a_1=21-2(1)^2\\\\a_1=19


a_2=21-2(2)^2\\\\a_2=13


a_3=21-2(3)^2\\\\a_3=3


a_4=21-2(4)^2\\\\a_4=-11


a_5=21-2(5)^2\\\\a_5=-29

Therefore, the first five terms of the sequence defined by the explicit formula a_n=21-2n^2 are 19, 13, 3, -11, -29.


5 0
3 years ago
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Lerok [7]
It is 1082. 

I hope it helps, you can do more on a calculator. :)))
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3 years ago
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Help please 50 PTS! I need this asap
mars1129 [50]

Answer:

How tall are you

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2 years ago
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