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uysha [10]
3 years ago
10

A pool owner adds a compound containing chlorine to the pool to disinfect it. However, too much of the compound is added. As a r

esult, the water becomes too acidic. What could the pool owner do to reduce the acidity of the pool?
He could add another acid to the pool to compete with the existing acid.
He could add a metal salt to the pool to precipitate the acid.
He could add a base to the pool to neutralize the acid.
Chemistry
2 answers:
MrMuchimi3 years ago
3 0

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

Cl_2+H_2O\rightarrow HOCl

HOCl\rightarrow HCl+O

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

Acid+Base\rightarrow Salt+water

Adding more acid would increase the acidity further.

dusya [7]3 years ago
3 0

Answer:

He could add a bass to the pool to neutralize the acid.

Explanation:

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Explanation:

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1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.
Anarel [89]

<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of carbon dioxide = 1 lb = 453.6 g   (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

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To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm   (Conversion factor:  1 psia = 0.068 atm)

V = Volume of carbon dioxide = 0.6ft^3=16.992L    (Conversion factor:  1ft^3=28.32L )

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R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the system = ?

Putting values in above equation, we get:

13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K

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8 0
3 years ago
Calculate the pressure exerted by an book of mass 20kg occupying an area of 2 m square.​
kotykmax [81]

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<u>Pressure = Force ÷ Area</u>

<u />

We are given that :

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<u />

So, force will be :

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Now, we can finally calculate pressure :

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What is the molarity of a 4.447 L solution
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use S= 1000w/ MV

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